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1 year ago

Describe how the basic measurements of length, volume, and mass were determined in the

Physics

1 answer:

Anna11 [10]1 year ago

4 0

the basic measurements of length, volume, and mass are 1 meter, 1 meter³ and 1kilogram.

One 10-millionth of the distance from the North Pole to the equator would equal one meter.

A cube with sides of one meter has a volume of one meter³.

The mass of 1,000 cubic centimeters of water is very close to (and was originally intended to be exactly) one kilograms.

but today a more precise way to define is available in which:

1 meter is defined as the distance traveled by light in 1/3×10⁸ sec.

The weight of a specific platinum-iridium prototype held by the International Bureau of Weights and Measures is defined as 1 kg.

moreover these measurements are man made and are not absolute and therefore many new units of measurement can be defined as long as they are fundamentally same everywhere.

learn more about metric system here:

brainly.com/question/2555957

#SPJ9

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What percentage of the original kinetic energy is convertible to internal energy?

schepotkina [342]

There would be very less percentage loss of the kinetic energy during the conversion to internal energy, assuming that there is less air in the surroundings. Also, the friction will contribute to the conversion where if it is, the percentage loses is negligible.

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3 years ago

Pls answer B And C Will Mark Brainlist. And 30 Points. :)

Vika [28.1K]

Answer:

use the formula for option B ( d/t = s )

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3 years ago

A ball is dropped from the top of a building.After 2 seconds, it’s velocity is measured to be 19.6 m/s. Calculate the accelerati

zlopas [31]

Answer:

acceleration, a = 9.8 m/s²

Explanation:

'A ball is dropped from the top of a building' indicates that the initial velocity of the ball is zero.

u = 0 m/s

After 2 seconds, velocity of the ball is 19.6 m/s.

t = 2s, v = 19.6 m/s

Using

v = u + at

19.6 = 0 + 2a

a = 9.8 m/s²

6 0

3 years ago

Read 2 more answers

A string under a tension of 50.4 N is used to whirl a rock in a horizontal circle of radius 2.51 m at a speed of 21.1 m/s. The s

Leokris [45]

Answer:

619.8 N

Explanation:

The tension in the string provides the centripetal force that keeps the rock in circular motion, so we can write:

$T=m\frac{v^2}{r}$

where

T is the tension

m is the mass of the rock

v is the speed

r is the radius of the circular path

At the beginning,

T = 50.4 N

v = 21.1 m/s

r = 2.51 m

So we can use the equation to find the mass of the rock:

$m=\frac{Tr}{v^2}=\frac{(50.4)(2.51)}{21.1^2}=0.284 kg$

Later, the radius of the string is decreased to

r' = 1.22 m

While the speed is increased to

v' = 51.6 m/s

Substituting these new data into the equation, we find the tension at which the string breaks:

$T'=m\frac{v'^2}{r'}=(0.284)\frac{(51.6)^2}{1.22}=619.8 N$

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3 years ago

Ted is a high school student. He is very good at math, but he is not a very good English student. He likes all of his teachers;

scoray [572]

I think the correct answer is

D) Ted associated being asked a question with embarrassment.

Glad I could help, and good luck!

AnonymousGiantsFan

3 0

3 years ago

Read 2 more answers