Answer:
6 x 6 x 3 cm
Step-by-step explanation:
The base of the box needs to fit the base of the hemisphere.
The maximum width and length of the hemisphere is the diameter of the base of the hemisphere (which is circular)
Diameter of a circle = 2r
As the radius = 3 cm, the diameter = 2 x 3 = 6 cm
Therefore, the width and length of the box should both be 6cm
The height of the box needs to accommodate the height of the hemisphere. The height of the hemisphere is the radius, so the height of the box should be 3 cm.
Therefore, the dimensions of the box should be 6 x 6 x 3 cm
The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound
<h3>Data obtained from the question</h3>
From the question given above, the following data were obtained:
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Work done (Wd) =?
<h3>How to determine the spring constant</h3>
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Spring constant (K) =?
F = Ke
Divide both sides by e
K = F/ e
K = 3 / 0.6
K = 5 pound/foot
Thus, the spring constant of the spring is 5 pound/foot
<h3>How to determine the work done</h3>
- Spring constant (K) = 5 pound/foot
- Extention (e) = 0.7 feet
- Work done (Wd) =?
Wd = ½Ke²
Wd = ½ × 5 × 0.7²
Wd = 2.5 × 0.49
Wd = 1.23 foot-pound
Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound
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Answer:
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Step-by-step explanation:
Answer:
7√(x) = 14
Step-by-step explanation:
The answer would be 16.
you have to multiply 4 and 8 which =32 and then divide 32 by 2 which =16