Using the arithmetic progression, If a theatre has 30 rows of seats there are 22 seats in the first row,26 in the second row, 30 in the third row, then the total number of people that the theatre hold is 2400
The total number of rows = 30
Number of seats in the first row = 22
Number of seats in the second row = 26
Number of seats in the third row = 30
Common difference= Second term - first term
= 26-22
= 4
The given sequence is in arithmetic progression
Sum of n terms =
Substitute the values in the equation
=
= 15[44+29×4]
= 15[44+116]
= 15×160
= 2400
Hence, using the arithmetic progression, if a theatre has 30 rows of seats and there are 22 seats in the first row,26 in the second row, 30 in the third row, then the total number of people that the theatre hold is 2400
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