In which part of the eye are eye floaters found?
Cornea.
<u>Vitreous humor</u>
Retina
Convex lens.
Answer:
The net force is 1350 kN
Solution:
As per the question:
Mass of man, m = 60 kg
Initial speed of the car, v = 15 m/s
Final speed of the car, v' = 0 m/s
Distance covered by the person before coming to rest, d = 5 mm = 
By using the third eqn of motion:
Thus the force on the person can be given by:
F = ma = 
Sun is the biggest mass in the ss
Answer:
The position of the particle is 6m
The velocity of the particle is 16 m/s in negative direction
The acceleration of the object is -40 m/s²
Explanation:
Given;
motion of the particle along a straight line as x = 6 + 4t² - t⁴
The position of the object when t = 2s
x = 6 + 4(2)² - (2)⁴
x = 6 + 16 - 16
x = 6m
The velocity of the object when t = 2s
Velocity = dx/dt
dx/dt = 8t - 4t³
when t = 2s
Velocity = 8(2) - 4(2)³
Velocity = 16 - 32
Velocity = -16m/s
Velocity = 16 m/s (in negative direction)
The acceleration of the object when t = 2s
Acceleration = d²x/dt² = 8 - 12t²
Acceleration = 8 - 12 (2)²
Acceleration = -40 m/s²
