Explanation:
It is given that,
Electric field strength, E = 20,000 N/C
Spacing between parallel-plate capacitor, d = 1 mm = 0.001 m
Initial velocity of electron, u = 0
Let v is the electron’s speed when it reaches the positive plate. The force acting on the electron is :
Also,
Using third equation of motion as :
v = 2649528.2599 m/s
or
So, the velocity of the electron when it reaches the positive plate is . Hence, this is the required solution.
Answer:
V = 31.62 m V
Explanation:
Given,
Voltage across thick membrane = ?
Thickness of the membrane, d = 5.5 n m
Electric field = 5.75 M V/m
we know
V = E d
V = 5.75 x 10⁶ x 5.5 x 10⁻⁹
V = 31.62 x 10⁻³ V
V = 31.62 m V
Hence, The Voltage across the membrane is equal to 31.62 m V.
The answer is A. the principal energy level
<h2>Why?</h2>The principal energy level or principal quantum number n, tell us about the position of an determined electron in the energy levels relative to the greater average distance of an electron from the nucleus, the larger the value of n and the higher its energy.
The principal energy levels contains n sublevels, orbitals and
electrons.
For example, the number 1, has one orbital which is contained in a energy sublevel, its called s orbital, and it's just an orbital with 2 electrons.
Have a nice day!
Answer:
3600 J
Explanation:
According to given question
P(rated)=60w
V= 120
I =0.50 A
t=600 second
Now,
Energy can be calculated as :
Where,
V is voltage
I is current
t is time in second
Now,
Putting the all value in above equation E
So,
Therefore, 36000 J energy use up by light bulb
Answer:
The Electric field will be 225.92 N/C
Explanation:
Given :
We know that the flux of the electric field through a close surface cab be calculated by using Gauss Law which is
Hence the Electric Field is calculated.
The answer founded out by you seems to be correct and very close to the exact answer and the concept you have used in your answer is also correct.