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lbvjy [14]
3 years ago
11

QUESTION 10

Physics
1 answer:
Vera_Pavlovna [14]3 years ago
5 0
Smaller-sized bags, I would think. There is less in the bags so she has less to eat. She would excersise a small bag off faster than a big bag.
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Three point charges are arranged on a line. Charge q3 = 5 nC and is at the origin. Charge q2 = - 3 nC and is at x = 4 cm. Charge
Taya2010 [7]

Answer:

q₁ = + 1.25 nC

Explanation:

Theory of electrical forces

Because the particle q₃ is close to two other electrically charged particles, it will experience two electrical forces and the solution of the problem is of a vector nature.

Known data

q₃=5 nC

q₂=- 3 nC

d₁₃=  2 cm

d₂₃ = 4 cm

Graphic attached

The directions of the individual forces exerted by q1 and q₂ on q₃ are shown in the attached figure.

For the net force on q3 to be zero F₁₃ and F₂₃ must have the same magnitude and opposite direction, So,  the charge q₁ must be positive(q₁+).

The force (F₁₃) of q₁ on q₃ is repulsive because the charges have equal signs ,then. F₁₃ is directed to the left (-x).

The force (F₂₃) of q₂ on q₃ is attractive because the charges have opposite signs.  F₂₃ is directed to the right (+x)

Calculation of q1

F₁₃ = F₂₃

\frac{k*q_{1}*q_3 }{(d_{13})^{2}  } = \frac{k*q_{2}*q_3 }{(d_{23})^{2}  }

We divide by (k * q3) on both sides of the equation

\frac{q_{1} }{(d_{13})^{2} } = \frac{q_{2} }{(d_{23})^{2} }

q_{1} = \frac{q_{2}*(d_{13})^{2}   }{(d_{23} )^{2}  }

q_{1} = \frac{5*(2)^{2} }{(4 )^{2}  }

q₁ = + 1.25 nC

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Rama09 [41]

Answer:

hope this helps i think the answer is C

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Distance = (30+40+50) = 120 km

It's back where it started, so displacement = zero

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Which of the following is an important step in the process of conflict resolution?
4vir4ik [10]
A would be the correct answer. Its the only one to make sense since you are trying to solve the conflict!
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_______is the product of a force and the time during which the force acts
saul85 [17]

Answer:

impulse is the product of a force and the time during which the force acts

Explanation:

i hope this will help you :)

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