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vivado [14]
2 years ago
5

What is the unit for measuring electric current? A.Volt B.ampere C.ohm D.coulomb

Physics
2 answers:
Pachacha [2.7K]2 years ago
8 0

Answer:

B. ampere

Explanation:

Edg 2020

ahrayia [7]2 years ago
6 0

Answer:

B. Ampere

Explanation: I took a test.

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Which is a sub-atomic particle?
Natalka [10]
A particle that is smaller than an atom or a cluster of particles.
4 0
3 years ago
Study the roller coaster diagram. Match the labels to the correct location on the roller coaster.
IRISSAK [1]

Answer:

A- Greatest Kinetic Energy

B- Increasing Potential Energy

C- Increasing Kinetic Energy

D- Greatest Potential Energy

Explanation:

hope this is right.

3 0
2 years ago
Read 2 more answers
A uniform thin wire is bent into a quarter-circle of radius a = 20.0 cm, and placed in the first quadrant. Determine the coordin
Mashcka [7]

Answer:

r_{cm}=[12.73,12.73]cm

Explanation:

The general equation to calculate the center of mass is:

r_{cm}=1/M*\int\limits {r} \, dm

Any differential of mass can be calculated as:

dm = \lambda*a*d\theta  Where "a" is the radius of the circle and λ is the linear density of the wire.

The linear density is given by:

\lambda=M/L=M/(a*\pi/2)=\frac{2M}{a\pi}

So, the differential of mass is:

dm = \frac{2M}{a\pi}*a*d\theta

dm = \frac{2M}{\pi}*d\theta

Now we proceed to calculate X and Y coordinates of the center of mass separately:

X_{cm}=1/M*\int\limits^{\pi/2}_0 {a*cos\theta*2M/\pi} \, d\theta

Y_{cm}=1/M*\int\limits^{\pi/2}_0 {a*sin\theta*2M/\pi} \, d\theta

Solving both integrals, we get:

X_{cm}=2*a/\pi=12.73cm

Y_{cm}=2*a/\pi=12.73cm

Therefore, the position of the center of mass is:

r_{cm}=[12.73,12.73]cm

5 0
3 years ago
Assume that a vaulter is able to carry a vaulting pole while running as fast
rewona [7]
A,walls
Speleleelelelekeke
8 0
3 years ago
Read 2 more answers
Gold, which has a mass of 19.32 g for each cubic centimeter of volume, is the most ductile metal and can be pressed into a thin
Dennis_Churaev [7]

Answer:

area = 5733.33  cm²

length = 5.47 ×10^{7} cm

Explanation:

Given data

density = 19.32 g/cm³

mass = 33.16 g

thickness = 3.000 µm = 3 ×10^{-4} cm

radius r = 1.000 µm = 1 ×10^{-4} cm

to find out

area of the leaf and  length of the fiber

solution

we know volume formula that is

volume = mass / density

volume = 33.16 /  19.32

volume = 1.72 cm³

we know that volume = thickness × area

so area

area = volume / thickness

area = 1.72 / 3 ×10^{-4}

area = 5733.33  cm²

and

we know volume = πr²L

so L = volume /  πr²

length = 1.72 / π(1×10^{-4})²

length = 5.47 ×10^{7} cm

3 0
3 years ago
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