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2 years ago

8

Two band members are marching toward each other beginning from opposite end zone goal lines (100 yards apart). One band member i

s playing a picolo and marching at 5 ft/s and the other is playing a sousaphone and marching at 1 ft/s. At what yard line do they meet?

1 answer:

Stella [2.4K]2 years ago

3 0

Answer:

17

Explanation:

answer is 16.6666 which is equal to 17

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Answer:

$\dfrac{d\theta}{dt} =-0.233\ rad/s$

Explanation:

given,

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let x be the distance of the bottom and y be the distance of the top of ladder.

x² + y² = 100

differentiating with respect to time we get

$2 x\dfrac{dx}{dt}+2y\dfrac{dy}{dt} = 0$ ..............(1)

when x = 8 and y = 6 and when \dfrac{dx}{dt} = 1.4ft/s

from equation (1)

now,

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$\dfrac{dy}{dt} = -\dfrac{5.6}{3}$

let the angle between the ladders be θ

$tan\theta = \dfrac{y}{x}$

y = xtan θ

$\dfrac{dy}{dt} =\dfrac{dy}{dt} tan\theta + x sec^2\theta\dfrac{d\theta}{dt}$

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$\dfrac{25}{2} \dfrac{d\theta}{dt} =\dfrac{-17.5}{6}$

$\dfrac{d\theta}{dt} =-0.233\ rad/s$

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In one of his books "On the Revolutions of the Heavenly Bodies", he published the renowned line which declares his theory.

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You are trying to hear your friend give directions to new store in town. But from your distance (1 point) of 15 m you only hear

Marat540 [252]

Answer:

option D

Explanation:

given,

Intensity of sound = 20 dB

distance = 15 m

intensity of sound is increased to = 50 dB

distance between the sound level = ?

Using relation

$L_2 = L_1 - |20(log \dfrac{r_2}{r_1})|$

L₁ = 20 dB L₂ = 50 dB r₁ = 15 m r₂ = ?

$log (\dfrac{r_2}{r_1}) = \dfrac{L_1 -L_2}{20}$

$\dfrac{r_2}{r_1}= 10^{\dfrac{|L_1 -L_2|}{20}}$

$r_2 =r_1 10^{\dfrac{|L_1 -L_2|}{20}}$

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r₂ = 0.47 m

r₂ = 47 cm

hence, the correct answer is option D

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