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Yakvenalex [24]
10 months ago
11

132 days to 125.4 days percent of change

Mathematics
2 answers:
sp2606 [1]10 months ago
8 0
.05% of change is the answer
Evgen [1.6K]10 months ago
5 0

Answer:

132 days to 125.4 days percent of change

Step-by-step explanation:

p= N-O/O x 100% where p is the percent change, is the New value and O is

the Old value. We are given the Old value (132) and the New value (125.4) which we can substitute into the formula to calculate the percent change:

p= 125.4-132/132 x 100%

p= -6.6/132 x 100%

p= (-660/132%)

p= -5%

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Answer:

a) [-0.134,0.034]

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Step-by-step explanation:

a) Since the variances are unknown, we use the t-test with 95% confidence interval, that is the significance level = 1-0.05 = 0.025.

Since we assume that the variances are equal, we use the pooled variance given as

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b) With 95% confidence, we can say that it is possible that the gaskets from shift 2 are, on average, wider than the gaskets from shift 1, because the mean difference extends to the negative interval or that the gaskets from shift 1 are wider, because the confidence interval extends to the positive interval.

c) Increasing the sample sizes results in a smaller margin of error, which gives us a narrower confidence interval, thus giving us a good idea of what the true mean difference is.

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