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telo118 [61]
1 year ago
12

finally, remind yourself the properties of light from the first lecture and qs1. if instead of pulses, the astronaut had sent a

continuous beam of green light. how would that light appear to those on the spaceship?
Physics
1 answer:
hjlf1 year ago
7 0

Although the green light flashes first, you are moving away from it, so it illuminates you at the same moment as the red light.

A green laser is frequently used by amateur astronomers because its visible beam may be used to point out stars and galaxies because it penetrates the atmosphere so far. Red lasers are less adaptable than green lasers. Each wave or component of light in a laser has been precisely aligned to form a single, strong beam.

Green DPSS lasers are the most popular and first emerged on the market about 2000. (also called diode-pumped solid-state frequency-doubled, DPSSFD). Due to the rarity of laser diodes in this wavelength region, they are more complicated than regular red laser pointers.

Green lasers have been used in head-mounted displays and laser guides for defense and security purposes. Amateur astronomers can also direct and track stars using green laser guides.

To learn more about a green light. Please visit the below link.

brainly.com/question/4503557

#SPJ4

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45 V =
Valentin [98]

Explanation:

https://educationalghana.news.blog/2021/08/09/geography-human-physical-and-practical-for-wassce-novdec-candidates/

8 0
2 years ago
A small object of mass 3.82 g and charge -16.5 µC is suspended motionless above the ground when immersed in a uniform electric f
horrorfan [7]

Answer:

2271.16N/C  upward

Explanation:

The diagram well illustrate all the forces acting on the mass. The weight is acting downward and the force is acting upward in other to balance the weight.since the question says it is motionless, then indeed the forces are balanced.

First we determine the downward weight using

W=mg\\g=9.81m/s^{2}

Hence for a mass of 3.82g 0r 0.00382kg we have the weight to be

W=0.00382kg*9.81m/s^{2}

W=0.0375N

To calculate the electric field,

E=f/q\\E=0.0375/16.5*10^{-6} \\E=2271.16N/C

Since the charge on the mass is negative, in order to generate upward force, there must be a like charge below it that is  repelling it, Hebce we can conclude that the electric field lines are upward.

Hence the magnitude of the electric force is 2271.16N/C and the direction is upward

4 0
3 years ago
22. State any three features of the electroscope.​
MatroZZZ [7]
-1- was created in the 1600 by william gilbert
-2-When the charge is positive, electrons in the metal of the electroscope are attracted to the charge and move upward out of the leaves. This results in the leaves to have a temporary positive charge and because like charges repel, the leaves separate. When the charge is removed, the electrons return to their original positions and the leaves relax
3-

An electroscope is made up of a metal detector knob on top which is connected to a pair of metal leaves hanging from the bottom of the connecting rod. When no charge is present the metals leaves hang loosely downward. But, when an object with a charge is brought near an electroscope, one of the two things can happen.
7 0
3 years ago
When sound travels through air, the particles _____. a. vibrate along the direction the wave travels b. vibrate but not in any f
Mandarinka [93]
Vibrate along the direction the wave travels
8 0
4 years ago
a car going 22 m/s accelerates to pass a truck. Five seconds later the car is going 35 m/s. Calculate the acceleration of the ca
Maksim231197 [3]
Using the formula

a\: = \frac{v - u}{t}

a = \frac{35 m/s \: - \: 22 m/s}{5s}

a = 2.6 {m/s^2}
5 0
3 years ago
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