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pantera1 [17]
3 years ago
7

The sun heats earth's atmosphere unevenly. this causes convection currents to move in large circles in the atmosphere. what is t

he result of convection currents in the atmosphere?
Physics
2 answers:
topjm [15]3 years ago
6 0
The answer is wind. we all know that this is often the horizontal drive of air. All wind is created by the not level heating of layer, that arrays convection currents in the signal. Convection currents on an enormous<span> scale make global winds; convection currents on a minor scale cause local winds.

Explanation:


</span>Convection currents area unit is known<span> in Earth's mantle. Heated mantle material is shown rising from deep </span>within<span> the mantle, </span>whereas cooler<span> mantle material sinks, </span>making<span> a convection current. </span>it's<span> thought that </span>this sort<span> of current is </span>responsible for<span> the movements of the plates of </span>crust.

<span>Convection is </span>one in each of the key<span> processes in </span>making<span> our weather. Convection is one </span>explanation for<span> rising air in our atmosphere, </span>sometimes heat<span> air rises </span>higher than<span> cold air.</span>
<span>Convection </span>happens once the planet<span> is heated </span>inconsistently<span>.

The air over </span>the planet can<span> heat </span>in step with how briskly the planet under that<span> heats. That </span>a part of<span> the atmosphere that heats </span>quicker can<span> expand.</span>
vladimir2022 [97]3 years ago
3 0

The answer is wind. We know that this is the horizontal drive of air. All wind is produced by the not level heating of Earth's surface, which arrays convection currents in signal. Convection currents on a big scale make global winds; convection currents on a minor scale cause local winds.

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Explanation:

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2 years ago
A physics professor demonstrates the Doppler effect by tying a 600 Hz sound generator to a 1.0-m-long rope and whirling it aroun
nalin [4]

Answer:

Therefore the the highest frequency is 620Hz and lowest frequency is 580Hz

Explanation:

Given data

Source Frequency fs=600Hz

Length r=1.0m

RPM=100 rpm

The speed of the generator is calculated as:

v_{s}=rw\\v_{s}=r(2\pi f)

Substitute the given values

v_{s}=(1.0m)2\pi (\frac{100}{60}rev/s )\\v_{s}=10.47m/s

For approaching generator the frequency is calculated as:

f_{+}=\frac{f_{s}}{1-\frac{v_{s}}{v} }\\f_{+}=\frac{600Hz}{1-\frac{10.47m/s}{343m/s} } \\f_{+}=620Hz

On the other hand,for the receding generator,Doppler's effect is expressed as:

 f_{-}=\frac{f_{s}}{1+\frac{v_{s}}{v} }\\f_{-}=\frac{600Hz}{1+\frac{10.47m/s}{343m/s} } \\f_{-}=580Hz

Therefore the the highest frequency is 620Hz and lowest frequency is 580Hz

8 0
3 years ago
What help in reversing direction of current of current​
Novay_Z [31]

Answer:

<em>To reverse the direction of an electric current, we simply reverse the voltage either automatically with the help of some switching circuitry or manually by changing the voltage source terminals connection.  </em>

Explanation:

For electric current to flow, there must be a potential difference, usually referred to as the voltage. The electric current flow is analogous to the flow of water under the action of a pump, through a series of pipe connections. The voltage is similar to the driving action of the pump, and current flows the same way water flows. The resistance due to drag on the pipe wall is equivalent to electric resistance. For current to flow in the reverse direction, the voltage or rather, the potential difference is changed, causing the current to flow in the opposite direction. This can be done by switching the terminals of the voltage source, or by automatic means. The automatic switching can be done with a transistor based circuitry.

3 0
3 years ago
Explanation for question i &amp; ii. Thank you.
suter [353]
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6 0
3 years ago
A runner is moving at a constant speed of 8.00 m/s around a circular track. If the distance from the runner to the center of the
Genrish500 [490]

Answer: Last option

2.27 m/s2

Explanation:

As the runner is running at a constant speed then the only acceleration present in the movement is the centripetal acceleration.

If we call a_c to the centripetal acceleration then, by definition

a_c =w^2r = \frac{v^2}{r}

in this case we know the speed of the runner

v =8.00\ m/s

The radius "r" will be the distance from the runner to the center of the track

r = 28.2\ m

a_c = \frac{8^2}{28.2}\ m/s^2

a_c = 2.27\ m/s^2

The answer is the last option

3 0
3 years ago
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