Craig is modeling the discovery of electromagnetism. Which procedure should he use?

The __________ energy in food is changed into mechanical energy by your muscles.

Orlov [11]

Potential energy which is the stored energy an object has waiting to be used

8 0

3 years ago

Topic Gravitational force amd firld strength.. help me please

I am Lyosha [343]

The gravitational force between m₁ and m₂ has magnitude

$F_{1,2} = \dfrac{Gm_1m_2}{x^2}$

while the gravitational force between m₁ and m₃ has magnitude

$F_{1,3} = \dfrac{Gm_1m_3}{(15-x)^2}$

where x is measured in m.

The mass m₁ is attracted to m₂ in one direction, and attracted to m₃ in the opposite direction such that m₁ in equilibrium. So by Newton's second law, we have

$F_{1,2} - F_{1,3} = 0$

Solve for x :

$\dfrac{Gm_1m_2}{x^2} = \dfrac{Gm_1m_3}{(15-x)^2} \\\\ \dfrac{m_2}{x^2} = \dfrac{m_3}{(15-x)^2} \\\\ \dfrac{(15-x)^2}{x^2} = \dfrac{m_3}{m_2} = \dfrac{60\,\rm kg}{40\,\rm kg} = \dfrac32 \\\\ \left(\dfrac{15-x}x\right)^2 = \dfrac32 \\\\ \left(\dfrac{15}x-1\right)^2 = \dfrac32 \\\\ \dfrac{15}x - 1 = \pm \sqrt{\dfrac32} \\\\ \dfrac{15}x = 1 \pm \sqrt{\dfrac32} \\\\ x = \dfrac{15}{1\pm\sqrt{\dfrac32}}$

The solution with the negative square root is negative, so we throw it out. The other is the one we want,

$x \approx 6.74\,\mathrm m$

5 0

3 years ago

A rotating lens mechanism blocks the view of the object as the new lenses are rotated. Be sure to click each lense firmly into p

Jobisdone [24]

I think that mechanism is called a "lens turret".

6 0

3 years ago

A clarinetist, setting out for a performance, grabs his 3.010 kg clarinet case (including the clarinet) from the top of the pian

KATRIN_1 [288]

Answer:

-0.481 m/s^2

Explanation:

The force equation of this problem is given as:

F - W = ma

where F = upward force holding the clarinet bag

W = downward force (weight of the clarinet)

The mass of the clarinet bag is 3.010 kg, therefore, its weight is:

W = mg

W = 3.010 * 9.8 = 29.498

F = 28.05 N

Therefore:

28.05 - 29.498 = 3.010 * a

-1.448 = 3.010a

=> a = -1.448 / 3.010

a = -0.481 m/s^2

The acceleration of the bag is downward.

8 0

4 years ago

The radius k of the equivalent hoop is called the radius of gyration of the given body. Using this formula, find the radius of g

Morgarella [4.7K]

Here is the full question:

The rotational inertia I of any given body of mass M about any given axis is equal to the rotational inertia of an equivalent hoop about that axis, if the hoop has the same mass M and a radius k given by:

$k=\sqrt{\frac{I}{M} }$

The radius k of the equivalent hoop is called the radius of gyration of the given body. Using this formula, find the radius of gyration of (a) a cylinder of radius 1.20 m, (b) a thin spherical shell of radius 1.20 m, and (c) a solid sphere of radius 1.20 m, all rotating about their central axes.

Answer:

a) 0.85 m

b) 0.98 m

c) 0.76 m

Explanation:

Given that: the radius of gyration $k=\sqrt{\frac{I}{M} }$

So, moment of rotational inertia (I) of a cylinder about it axis = $\frac{MR^2}{2}$