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4 years ago

Two students apply force to a box at rest on the floor.

Chemistry

1 answer:

Scilla [17]4 years ago

6 0

Answer:

10 N Left

Explanation:

Given parameters;

Forces acting on the box

Left force = 40N

Right force = 30N

Unknown:

Net force on the box and the direction = ?

Solution:

Force is a pull or push on a body;

← BODY →

40N 30N

The forces acting on the body are in the opposite directions, the greater force will determine the direction of pull.

Net force = Left force - Right force = 40 - 30 = 10N

The force will be directed left with a net value of 10N

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A solution with a higher concentration of hydroxide ions (oh-) than hydrogen ions (h+)

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3 years ago

What would be the composition and ph of an ideal buffer prepared from lactic acid (ch3chohco2h), where the hydrogen atom highlig

Mashutka [201]

Answer:

$P_H =2.86$

$c=1.4\times 10^{-4}$

Explanation:

first write the equilibrium equaion ,

$C_3H_6O_3$ ⇄ $C_3H_5O_3^{-} +H^{+}$

assuming degree of dissociation $\alpha$ =1/10;

and initial concentraion of $C_3H_6O_3$ =c;

At equlibrium ;

concentration of $C_3H_6O_3 = c-c\alpha$

$[C_3H_5O_3^{-} ]= c\alpha$

$[H^{+}] = c\alpha$

$K_a = \frac{c\alpha \times c\alpha}{c-c\alpha}$

$\alpha$ is very small so $1-\alpha$ can be neglected

and equation is;

$K_a = {c\alpha \times \alpha}$

$[H^{+}] = c\alpha$ = $\frac{K_a}{\alpha}$

$P_H =- log[H^{+} ]$

$P_H =-logK_a + log\alpha$

$K_a =1.38\times10^{-4}$

$\alpha = \frac{1}{10}$

$P_H= 3.86-1$

$P_H =2.86$

composiion ;

$c=\frac{1}{\alpha} \times [H^{+}]$

$[H^{+}] =antilog(-P_H)$

$[H^{+} ] =0.0014$

$c=0.0014\times \frac{1}{10}$

$c=1.4\times 10^{-4}$

6 0

4 years ago

Calculate the pressure exerted by an book of mass 20kg occupying an area of 2 m square.

kotykmax [81]

The answer is 100 Pa.

The formula for calculating pressure is :

Pressure = Force ÷ Area

We are given that :

mass = 20 kg
area = 2 m²

We also know that :

Force = mass ×g

So, force will be :

F = 20 × 10
F = 200 N

Now, we can finally calculate pressure :

P = 200 ÷ 2
P = 100 Pa

8 0

2 years ago