The value of the tension in the right rope,
, in terms of the weight<em> W</em>, and the dimensions, <em>L</em>, and <em>x</em>, obtained by finding the moment about the point the left rope is attached to the beam, can be presented as follows;

<h3>What is a moment of a force about a point?</h3>
The moment of a force is the product of the force and the perpendicular distance from the line of action of the force to the point.
Part of the question includes;
A weight <em>W</em> hanging on a beam of length <em>L</em> attached to two ropes with tensions,
and
, at a distance <em>x</em> from the left rope with tension, 
At equilibrium, we get;
∑F = 0
Therefore;
W =
+ 
The sum of the moment is zero, ∑M = 0
Therefore;
Clockwise moment about the point of contact, <em>P</em>, of
and the beam, W × x = Anticlockwise moment about point <em>P</em>,
× L
W × x =
× L
Therefore;

Learn more about equilibrium of forces and moments here:
brainly.com/question/27884146
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