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mario62 [17]
1 year ago
15

Solve for tr , the tension in the right rope. Express your answer in terms of w and the dimensions l and x. Not all of these var

iables may show up in the solution.
Mathematics
1 answer:
natta225 [31]1 year ago
8 0

The value of the tension in the right rope, T_R, in terms of the weight<em> W</em>, and the dimensions, <em>L</em>, and <em>x</em>, obtained by finding the moment about the point the left rope is attached to the beam, can be presented as follows;

T_R=\dfrac{W \times x}{L}

<h3>What is a moment of a force about a point?</h3>

The moment of a force is the product of the force and the perpendicular distance from the line of action of the force to the point.

Part of the question includes;

A weight <em>W</em> hanging on a beam of length <em>L</em> attached to two ropes with tensions, T_L and T_R, at a distance <em>x</em> from the left rope with tension, T_L

At equilibrium, we get;

∑F = 0

Therefore;

W =  T_L + T_R

The sum of the moment is zero, ∑M = 0

Therefore;

Clockwise moment about the point of contact, <em>P</em>, of  T_L and the beam, W × x = Anticlockwise moment about point <em>P</em>, T_R × L

W × x = T_R × L

Therefore;

T_R = \dfrac{W \times x}{L}

Learn more about equilibrium of forces and moments here:

brainly.com/question/27884146

#SPJ1

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Report this clown who put the first answer he’s trying to get your ip.
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Akeem is carrying water in a bucket, but is unsure how many gallons it holds. He knows that the bucket and water weigh 32.49 pou
bixtya [17]

Answer:

Step-by-step explanation:

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What is the equation of the line that has a slope of 3 and passes through the point (1, –2)?
lesya [120]

Answer:

y = 3x - 5

Step-by-step explanation:

The equation of a line in slope- intercept form is

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Here m = 3 , thus

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To find c substitute (1, - 2) into the partial equation

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6 0
3 years ago
Use a net to find the surface Area of the square pyramid The height of the pyramid is 9 yes and the base sides are all 2.5 yrds
Cerrena [4.2K]

Answer:

Area = 51.68yd^2

Step-by-step explanation:

Given

h = 9yd -- height

a = 2.5yd --- base sides

Required

Determine the surface area

The net is not given. So, I will solve directly.

The surface area is calculated as:

Area = a^2 + 2a\sqrt{\frac{a^2}{4} + h^2}

So, we have:

Area = 2.5^2 + 2*2.5\sqrt{\frac{2.5^2}{4} + 9^2}

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