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mario62 [17]
1 year ago
15

Solve for tr , the tension in the right rope. Express your answer in terms of w and the dimensions l and x. Not all of these var

iables may show up in the solution.
Mathematics
1 answer:
natta225 [31]1 year ago
8 0

The value of the tension in the right rope, T_R, in terms of the weight<em> W</em>, and the dimensions, <em>L</em>, and <em>x</em>, obtained by finding the moment about the point the left rope is attached to the beam, can be presented as follows;

T_R=\dfrac{W \times x}{L}

<h3>What is a moment of a force about a point?</h3>

The moment of a force is the product of the force and the perpendicular distance from the line of action of the force to the point.

Part of the question includes;

A weight <em>W</em> hanging on a beam of length <em>L</em> attached to two ropes with tensions, T_L and T_R, at a distance <em>x</em> from the left rope with tension, T_L

At equilibrium, we get;

∑F = 0

Therefore;

W =  T_L + T_R

The sum of the moment is zero, ∑M = 0

Therefore;

Clockwise moment about the point of contact, <em>P</em>, of  T_L and the beam, W × x = Anticlockwise moment about point <em>P</em>, T_R × L

W × x = T_R × L

Therefore;

T_R = \dfrac{W \times x}{L}

Learn more about equilibrium of forces and moments here:

brainly.com/question/27884146

#SPJ1

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In a trapezoid, adjacent angles are supplementary, meaning they add up to 180°. ∠W and ∠WXY are adjacent, so they are supplementary. 180° - 73° = 107°.

Another way to do this is to know that there are 360° in a trapezoid. This is a right trapezoid, so two of the angles are 90°. One angle is 73°. 90° + 90° + 73° = 253°. 360° - 253° = 107°.

I hope this helps :))

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