Answer:
75 m
Explanation:
The distance x for a uniform acceleration is given by the equation:

The given values are:
a = 6 m/s², t = 5 s, v₀ = 0, x₀ = 0
The mass percent composition of aluminum is 52.9% in aluminum oxide.
Mass of the aluminum = 3.53 g
Mass of the aluminum oxide = 6.67 g.
The mass percent of a substance is the mass of the substance divided by the mass of the compound into 100.
Aluminum reacts with oxygen to form aluminum oxide.
The overall balanced equation for the reaction is,


The mass percent composition of aluminum in the aluminum oxide is,



= 52.9 %
Therefore, the mass percent composition of aluminum is 52.9% in aluminum oxide.
To know more about aluminum oxide, refer to the below link:
brainly.com/question/25869623
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The height of the bullet when the velocity is zero is 256 ft.
<h3>Height of the bullet when the velocity is zero </h3>
The height of the bullet when the velocity is zero is determined by taking derivative of the function as shown below;

The height of the bullet at this time is calculated as follows;

Learn more about height of projectiles here: brainly.com/question/10008919