The mass of zinc required to react with HNO3 is 3.45 g
<h3>What is moles of HNO3 reacting?</h3>
The moles of HNO3 reacting is calculated using the formula below:
- moles = concentration × volume
volume = 0.850
volume = 125.0 mL = 0.125 L
Moles of HNO3 = 0.850 × 0.125 = 0.10625 moles
Equation of reaction:
Zn + 2 HNO3 --> Zn(NO3)2 + H2
2 moles of HNO3 reacts with 1 mole of Zn.
moles of zinc reacting = 0.10625/2 = 0.053125
Mass of zinc = moles × molar mass
molar mass of Zn = 65
Mass of zinc = 0.053125 × 65
mass of Zn = 3.45 g
Therefore, the mass of zinc will completely react with 125.0 mL of a solution of nitric acid (HNO3) which has concentration of 0.850M is 3.45 g
Learn more about moles at: brainly.com/question/15356425
Answer:
The number following the name of the element is the number of subatomic particles inside the nucleus of the atom. This means that it is the mass number of the isotope. The average atomic mass of the element is the sum of the products of the percentage abundance and mass number of the naturally occurring isotopes.
Since, the average atomic mass of the hydrogen is nearest to 1 then, the most abundant isotope should be hydrogen-1.
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