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liraira [26]
3 years ago
15

Osmium (Os) is the densest element known (density =22.57 g/cm^3). Calculate the mass in pounds and in kilograms of an Os sphere

15 cm in diameter (about the size of a grapefruit) (volume of a sphere of radius r is 4/3Ïr^3).
Chemistry
1 answer:
Amiraneli [1.4K]3 years ago
7 0

<u>Answer:</u> The mass of osmium in kilograms and in pounds are 318.9141 kg and 703.085 pounds.

<u>Explanation:</u>

To calculate the volume of sphere, we use the formula:

V=\frac{4}{3}\pi r^3

where,

r = radius of sphere

We are given:

Radius of osmium = 15 cm

Volume of osmium = \frac{4}{3}\times 3.14\times (15)^3=14130cm^3

Density of osmium = 22.57g/cm^3

To calculate mass of a substance, we use the equation:

Density=\frac{Mass}{Volume}

Putting values in above equation, we get:

22.57g/cm^3=\frac{\text{Mass of osmium}}{14130cm^3}\\\\\text{Mass of osmium}=318914.g

To convert the given mass into kilo grams and pounds, we use the conversion factors:

1 kg = 1000 grams

So, 318914.1g=318914.1g\times \frac{1kg}{1000g}=318.9141kg

And,

1 pound = 453.592 g

So, 318914.1g=318914.1g\times \frac{1pound}{453.592g}=703.085pounds

Hence, the mass of osmium in kilograms and in pounds are 318.9141 kg and 703.085 pounds.

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Using molar masses

80.912 g HBr reacts with  39.997 g of Naoh to give 18.007 g water

so 1 gram of NaOH reacts with 2.023 g of HBR   
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A train travels at a speed of 30 miles per hour. If 1 mile = 1.6 kilometers, how fast is the train traveling in kilometers per m
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The answer 
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v = </span><span>30 miles per hour
</span><span>1 mile = 1.6 kilometers

just do the calculus by changing miles to kilometers
 </span>1 mile = 1.6 kilometers, so 30 miles= 1.6 km x 30 = 48 km
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the answer is
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7 0
3 years ago
What is the mass if 1.72 moles of sodium nitrate
alexgriva [62]

Answer:

146 g

Explanation:

Step 1. Calculate the <em>molar mass</em> of NaNO₃

Na =                    22.99

  N =                     14.01

3O = 3 × 16.00 = 48.00

               Total = 85.00 g/mol

Step 2. Calculate the <em>mass</em>  of NaNO₃

Mass of NaNO₃ = 1.72 × 85.00/1

Mass of NaNO₃ = 146 g

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If a lab requires each lab group to have 25ml of a solution and it takes 15 grams of CuNO3 to make 1 liter of solution how many
tino4ka555 [31]

We need to do some general algebra here.

We will find that you need 8.25 grams of CuNO₃ to make enough solution for the 22 labs.

<em>We know that:</em>

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  • it takes 15 g of CuNO₃ to make one L of that solution.
  • There are 22 labs.

Because each lab needs 25 ml of solution, 22 labs will need that amount 22 times, so the <u>total amount of solution needed</u> is:

22*25ml = 550 ml

Now we know that we need 15 grams to make one liter of solution, and:

1 L = 1000ml

Then you need 15g to make 1000ml

and x (we want to find this amount) to make 550ml

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Now we can take the quotient between these two equations:

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And now we can solve this for x:

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So you need 8.25 grams of CuNO₃ to make enough solution for the 22 labs.

If you want to learn more, you can read:

brainly.com/question/8743486

5 0
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taurus [48]

Answer:

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