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liraira [26]
3 years ago
15

Osmium (Os) is the densest element known (density =22.57 g/cm^3). Calculate the mass in pounds and in kilograms of an Os sphere

15 cm in diameter (about the size of a grapefruit) (volume of a sphere of radius r is 4/3Ïr^3).
Chemistry
1 answer:
Amiraneli [1.4K]3 years ago
7 0

<u>Answer:</u> The mass of osmium in kilograms and in pounds are 318.9141 kg and 703.085 pounds.

<u>Explanation:</u>

To calculate the volume of sphere, we use the formula:

V=\frac{4}{3}\pi r^3

where,

r = radius of sphere

We are given:

Radius of osmium = 15 cm

Volume of osmium = \frac{4}{3}\times 3.14\times (15)^3=14130cm^3

Density of osmium = 22.57g/cm^3

To calculate mass of a substance, we use the equation:

Density=\frac{Mass}{Volume}

Putting values in above equation, we get:

22.57g/cm^3=\frac{\text{Mass of osmium}}{14130cm^3}\\\\\text{Mass of osmium}=318914.g

To convert the given mass into kilo grams and pounds, we use the conversion factors:

1 kg = 1000 grams

So, 318914.1g=318914.1g\times \frac{1kg}{1000g}=318.9141kg

And,

1 pound = 453.592 g

So, 318914.1g=318914.1g\times \frac{1pound}{453.592g}=703.085pounds

Hence, the mass of osmium in kilograms and in pounds are 318.9141 kg and 703.085 pounds.

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How many moles are in 125g of water?
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To calculate number of moles, all you do is divide the given mass by the molecular molar mass: 

<span>i.e. 125g / 18g = 6.94444g </span>

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3 years ago
A student is given a 2.002 g sample of unknown acid and is told that it might be butanoic acid, a monoprotic acid (HC4H7O2, equa
Elina [12.6K]

<u>Answer:</u> The identity of the unknown acid is butanoic acid or ascorbic acid.

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}

Molarity of NaOH solution = 0.570 M

Volume of solution = 39.55 mL

Putting values in above equation, we get:

0.570M=\frac{\text{Moles of NaOH}\times 1000}{39.55}\\\\\text{Moles of NaOH}=\frac{0.570\times 39.55}{1000}=0.0225mol

The chemical equation for the reaction of NaOH and monoprotic acid follows:

NaOH+HX\rightarrow NaX+H_2O

By Stoichiometry of the reaction:

1 mole of NaOH reacts with 1 mole of HX

So, moles of monoprotic acid = 0.0225 moles

The chemical equation for the reaction of NaOH and diprotic acid follows:

2NaOH+H_2X\rightarrow 2NaX+2H_2O

By Stoichiometry of the reaction:

2 moles of NaOH reacts with 1 mole of diprotic acid

So, moles of diprotic acid = \frac{0.0225}{2}=0.01125moles

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

  • <u>For butanoic acid:</u>

Mass of butanoic acid = 2.002 g

Molar mass of butanoic acid = 88 g/mol

Putting values in above equation, we get:

\text{Moles of butanoic acid}=\frac{2.002g}{88g/mol}=0.02275mol

  • <u>For L-tartaric acid:</u>

Mass of L-tartaric acid = 2.002 g

Molar mass of L-tartaric acid = 150 g/mol

Putting values in above equation, we get:

\text{Moles of L-tartaric acid}=\frac{2.002g}{150g/mol}=0.0133mol

  • <u>For ascorbic acid:</u>

Mass of ascorbic acid = 2.002 g

Molar mass of ascorbic acid = 176 g/mol

Putting values in above equation, we get:

\text{Moles of ascorbic acid}=\frac{2.002g}{176g/mol}=0.01137mol

As, the number of moles of butanoic acid and ascorbic acid is equal to the number of moles of acid getting neutralized.

Hence, the identity of the unknown acid is butanoic acid or ascorbic acid.

5 0
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