Answer:
C₂H₂ + 3H₂ ⟶ 2CH₄
Explanation:
The initial concentrations are:
[CH₄] = 6.30 ÷ 6.00 = 1.05 mol·L⁻¹
[C₂H₂] = 4.20 ÷ 6.00 = 0.700 mol·L⁻¹
[H₂] = 11.15 ÷ 6.00 = 1.858 mol·L⁻¹
2CH₄ ⇌ C₂H₂ + 3H₂
I/mol·L⁻¹: 1.05 0.700 1.858
![Q = \dfrac{\text{[C$_{2}$H$_{2}$][H$_{2}$]}^{3}}{\text{[CH$_{4}$]}^{2}} = \dfrac{ 0.700\times 1.858^{3}}{1.05^{2}}= 4.07](https://tex.z-dn.net/?f=Q%20%3D%20%5Cdfrac%7B%5Ctext%7B%5BC%24_%7B2%7D%24H%24_%7B2%7D%24%5D%5BH%24_%7B2%7D%24%5D%7D%5E%7B3%7D%7D%7B%5Ctext%7B%5BCH%24_%7B4%7D%24%5D%7D%5E%7B2%7D%7D%20%3D%20%5Cdfrac%7B%200.700%5Ctimes%201.858%5E%7B3%7D%7D%7B1.05%5E%7B2%7D%7D%3D%204.07)
Q > K
That means we have too many products.
The reaction will go to the left to get rid of the excess products.
C₂H₂ + 3H₂ ⟶ 2CH₄
Answer:
water, as there is 0.01% of itis left, mainly from polar caps, potable water is present, if it is not used carefully, then there will be no potable water for us to drink
Explanation:
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Answer :
The amount of sulfur emitted by a smokestack before and after the scrubber is attached
Answer:
The answer is C)
Explanation:
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Answer:
3.75 g/mL
Explanation:
Density can be calculated using the following formula:
Density = mass (g) / volume (mL)
You have been given the mass of the mineral sample (75 g). To find the volume, you need to determine the amount of space that the sample takes up when it is placed in the water. This can be done by subtracting the initial water volume from the final water volume.
Volume = Final - Initial
Volume = 40 mL - 20 mL
Volume = 20 mL
Now, you can calculate the density of the mineral sample.
Density = mass / volume
Density = 75 g / 20 mL
Density = 3.75 g/mL
