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3 years ago

Can you use carbon dioxide in the dark

Chemistry

1 answer:

S_A_V [24]3 years ago

5 0

Answer:

If you already have a solenoid, there is nothing wrong with running CO2 with the lights only. It will save CO2, and prevent excessive CO2 levels at night. Some think the CO2 should be up to max levels when the lights go on.

Explanation:

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During respiration, energy is retrieved from the high-energy bonds found in certain organic molecules. Which of the following, i

babunello [35]

Answer:

(A.) CO2, H2O

Explanation:

The chemical equation for respiration process is:

$C_{6}H_{12} O_{6}$ + $6O_{2}$ → $6CO_{2}$ + $6H_{2} O$ + ATP↑

Energy is released during the biochemical process in the organism's cells in form of ATP. Byproducts of the reaction are carbon dioxide and water molecules.

Let me know if you require any further assistance.

4 0

3 years ago

If the empirical formula of a compound is C2H5 and the Molecular mass is 87g/mol what is the molecular formula?

frez [133]

C6H15, C2H5 has a molar mass of 29g/mol. 87 divided by 29 is 3. Then multiply each element subscript by 3

6 0

3 years ago

In the molecular orbital model of cyclobutadiene, how many -antibonding molecular orbitals are there?

Citrus2011 [14]

There are one antibonding molecular orbitals present in molecular orbital model of c.

The cyclobutadiene has a pi system comprised of four individual atomic p - orbital and thus should have a four pi molecular orbitals. The compound is the prototypical antiaromatic hydrocarbon with 4 $\pi$ - electrons . Its rectangular structure is the result of jahn teller reaction which disorder the molecule and lowers its symmetry , converting the triplet to a singlet ground state. It is a small annulene . The delocalisation energy of the $\pi$ electrons of the cyclobutene is predicted to be zero .

To learn more about antibonding molecular orbitals click here

brainly.com/question/14970060

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2 years ago

1. Explain how groups 1A-8A in the periodic table are organized by their number of valence electrons.

nirvana33 [79]

Explanation:

1. Explain how groups 1A-8A in the periodic table are organized by their number of valence electrons.

The valence electrons in an atom are the outermost shell electrons. They are the most loosely held electrons in an atom.

Coincidentally, the periodic table of elements divided into vertical groups and horizontal periods can be said to be arranged according to the number of valence electrons.

Atomic numbers are used to arrange elements on the periodic table.
Down a group, the number of electronic shell increases. More electrons are added to new energy levels.
As we move from left to right across a period, the number of electrons in elements increases but electronic shell is the same.
Down a group electronic shell increases but the number of valence electrons are the same.
All elements in Group 1A has just one valence electrons, Group 2A has two valence electrons.........Group 8A has eight valence electrons.
Moving across groups is synonymous to moving from left to right on the periodic table.
Due to this trend, the periodic table is arranged based on the number of valence electrons.

3. explain how you know the number of valence electrons for each group.

The number of valence electrons in a group is the group number:

Group Number valence electrons

1A 1

2A 2

3A 3

4A 4

5A 5

6A 6

7A 7

8A 8

learn more:

Periodic table brainly.com/question/1971327

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6 0

3 years ago

1. Show that heat flows spontaneously from high temperature to low temperature in any isolated system (hint: use entropy change

Inga [223]

Answer:

1 ) Δs ( entropy change for hot block ) = - Q / th ( -ve shows heat lost to cold block )

Δs ( entropy change for cold block ) = Q / tc

∴ Total Δs = ΔSc + ΔSh

= Q/tc - Q/th

2) ΔSdecomposition = Δh / Temp = ( 181.6 * 10^3 / 773 ) = 234.928 J/k

Explanation:

<u>1) To show that heat flows spontaneously from high temperature to low temperature </u>

example :

Pick two(2) solid metal blocks with varying temperatures ( i.e. one solid block is hot and the other solid block is cold )

Place both blocks for time (t ) in an insulated system to reduce heat loss or gain to or from the environment

Check the temperature of both blocks after time ( t ) it will be observed that both blocks will have same temperature after time t ( first law of thermodynamics )

Δs ( entropy change for hot block ) = - Q / th ( -ve shows heat lost to cold block )

Δs ( entropy change for cold block ) = Q / tc

∴ Total Δs = ΔSc + ΔSh

= Q/tc - Q/th

<u>2) Entropy change for Decomposition of mercuric oxide </u>

2HgO (s) → 2Hg(l) + O₂ (g)

Δs = positive

there is transition from solid to liquid and the melting point of mercury ( the point at which reaction will take place ) = 500⁰C

hence ΔSdecomposition = S⁻ Hg - S⁻ HgO =

Δh of reaction = 181.6 KJ

Temp = 500 + 273 = 773 k

hence ΔSdecomposition = Δh / Temp = ( 181.6 * 10^3 / 773 ) = 234.928 J/k

8 0

3 years ago