Mols CuSO4 = M x L = 1.50 x 0.150 = 0.225
<span>mols KOH = 3.00 x 0.150 = 0.450 </span>
<span>specific heat solns = specific heat H2O = 4.18 J/K*C </span>
<span>CuSO4 + 2KOH = Cu(OH)2 + 2H2O </span>
<span>q = mass solutions x specific heat solns x (Tfinal-Tinitial) + Ccal*deltat T </span>
<span>q = 300g x 4.18 x (31.3-25.2) + 24.2*(31.3-25.2) </span>
<span>dHrxn in J/mol= q/0.225 mol CuSO4 </span>
<span>Then convert to kJ/mol
</span>
The formula of butane is C4H10 but I don't how many atoms it contains though
The choices that should have accompanied this question were:
A. 1
<span>B. 2 </span>
<span>C. 3 </span>
<span>D. 4
</span>
My answer is B. 2.
Below is an explanation, I found while doing the research.
<span>Phosphate needs 3 electrons each totaling 6 electrons so each zinc will need to give up 2 electrons.
Phosphate wants to imitate the electron configuration of Argon because noble configurations are the most stable. With P getting the extra electrons the valence shell will be 3s2 3p6, which is the same as Argon. Without the extra electrons, the P valence shell looks like this 3s2 3p3, now you can see why each phosphorus wants 3 more electrons, that will make it 3s2 3p6, just like Argon.</span>
Explanation:
When we add a non-volatile solute in a solvent then due to the impurity added to the solution there will occur an increase in the boiling point of the solution.
This increase in boiling point will be known as elevation in boiling point.
As one beaker contains seawater (water having NaCl) will have some impurity in it. So, more temperature is required by seawater to escape into the atmosphere.
Whereas another beaker has only pure water so it is able to easily escape into the atmosphere since, it contains no impurity.
Thus, we can conclude that level of pure water will decrease more due to non-volatile solute present in it as compared to seawater.
The answer is false because it goes in a full 360 degree circle
