According to Gases law, we know,
PV/T = Constant
So, P₁V₁/T₁ = P₂V₂/T₂
Here, P₁ = 108 kPa
V₁ = 592.2 mL
T₁ = 10+273 = 283 K
P₂ = ?
V₂ = 750 mL
T₂ = 28.9+273 = 301.9
Substitute their values,
108 * 592.2 / 283 = P₂ * 750 / 301.9
P₂ = 63957.6 * 301.9 / 283 * 750
P₂ = 19308799.44 / 212250
P₂ = 90.97 kPa
In short, Your Final Answer would be: 90.97 kPa
Hope this helps!
Density is found by dividing mass over volume:
d=M/V. In this problem, we know the density, and the mass. Solve the general equation for volume, then enter the values from the problem and evaluate:
d=m/v [multiply v to both sides, then divide d from both sides]
v=m/d
v=83.8g/(2.33g/cm³)
v=35.965 cm³
v=36.0 cm³ to three significant figures (since your given information only has 3 sig figs)
Answer:
The volume of basketball is 7216.5 cm³.
Explanation:
Given data:
Radius of ball = 12 cm
Volume of ball = ?
Solution:
We will apply the volume formula of sphere.
V = 4/3 ×π×r³
we know that,
π = 22/7
r = 12 cm
Now we will put the values in formula.
V = 4/3 × 3.14 × (12 cm)³
V = 4/3 × 3.14 ×1728 cm³
V = 7216.5 cm³
Thus, the volume of basketball is 7216.5 cm³.
At first quarter and last quarter, the Moon lies perpendicular to a line between Earth and the Sun. We see exactly half of the Moon illuminated by the Sun — the other half lies in shadow. Hope it helps :)
