Answer:
Less than 0.033 M:
![[Z]_{eq}=2.4x10^{-3}M](https://tex.z-dn.net/?f=%5BZ%5D_%7Beq%7D%3D2.4x10%5E%7B-3%7DM)
Explanation:
Hello,
In this case, the described equilibrium is:
Thus, the law of mass action is:
![K=\frac{[Z]^2}{[A]^2[B]}=0.43](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BZ%5D%5E2%7D%7B%5BA%5D%5E2%5BB%5D%7D%3D0.43)
Nevertheless, given the initial concentration of Z that is 0.033 M, we should invert the equilibrium since the reaction will move leftwards:
![\frac{1}{K}=\frac{[A]^2[B]}{[Z]^2}=\frac{1}{0.43}=2.33](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BK%7D%3D%5Cfrac%7B%5BA%5D%5E2%5BB%5D%7D%7B%5BZ%5D%5E2%7D%3D%5Cfrac%7B1%7D%7B0.43%7D%3D2.33)
Know, by introducing the change 
due to the reaction extent, we can write:
Which has the following solution:
But the correct solution is 
since the other solutions make the equilibrium concentration of Z negative which is not possible. In such a way, its concentration at equilibrium is:
![[Z]_{eq}=0.033M-2(0.0153M)](https://tex.z-dn.net/?f=%5BZ%5D_%7Beq%7D%3D0.033M-2%280.0153M%29)
Which is clearly less than 0.033 M since the addition of a product shift the reaction leftwards in order to reestablish equilibrium (Le Chatelier's principle).
Regards.
Answer:
2.275x10⁶g of CN⁻¹ were dissolved in the sample
Explanation:
Molarity is defined as the ratio between moles of solute and liters of solution.
If a CN⁻¹ solution has a concentration of 25mM, there are 0.025 moles of CN⁻¹ per liter of solution.
If the sample has a colume of 3.5x10⁶L, moles of CN⁻¹ are:
3.5x10⁶L × (0.025moles / L) = <em>8.75x10⁴ moles of CN⁻¹ in the sample of water.</em>
In grams (As molar mass of CN⁻¹ is 26g/mol):
8.75x10⁴ moles CN⁻¹ × (26g / mol) = <em>2.275x10⁶g of CN⁻¹ were dissolved in the sample</em>
Answer:
An atom is the basic particle elements are made from
