Answer:
C, The energy contained within the nucleus of an atom
Explanation:
The working equation for this problem is average atomic mass
is equal to the summation of the product of relative abundance and mass of
isotope. In this problem, just subtract the % abundance of Ag-107 to 100. Thus
the % abundance of Ag-109 is 48.16.
C is the answer.. B and D don't have anything to do with speed
Answer:
The speed of wavelength is 3.0 ×10³ m/s.
Explanation:
Given data:
De Broglie wavelength = 132 pm (132×10⁻¹² m)
Speed of wavelength = ?
Solution:
Formula:
λ = h/mv
λ = wavelength
h = planck's constant
m = mass of proton
v = speed
now we will put the values in formula.
132×10⁻¹² m = 6.63 ×10⁻³⁴ j.s / 1.67 ×10⁻²⁷ kg × v
v = 6.63 ×10⁻³⁴ j.s / 1.67 ×10⁻²⁷ kg × 132×10⁻¹² m
j = kg m²/s²
v = 6.63 ×10⁻³⁴ kg m²/s / 1.67 ×10⁻²⁷ kg × 132×10⁻¹² m
v = 6.63 ×10⁻³⁴ kg m²/s / 220.44 ×10⁻³⁹ kg.m
v = 0.03×10⁵ m/s
v = 3.0 ×10³ m/s
The speed of wavelength is 3.0 ×10³ m/s.
Left to write elements differ in their protons.
