Factor the following:
2 x^3 + x^2 - 18 x - 9
Factor terms by grouping. 2 x^3 + x^2 - 18 x - 9 = (2 x^3 + x^2) + (-18 x - 9) = x^2 (2 x + 1) - 9 (2 x + 1):
x^2 (2 x + 1) - 9 (2 x + 1)
Factor 2 x + 1 from x^2 (2 x + 1) - 9 (2 x + 1):
(2 x + 1) (x^2 - 9)
x^2 - 9 = x^2 - 3^2:
(2 x + 1) (x^2 - 3^2)
Factor the difference of two squares. x^2 - 3^2 = (x - 3) (x + 3):
Answer: (x - 3) (x + 3) (2 x + 1) thus the Answer is C.
T(n)=6-1=5
that means all terms are 5 because n does not appear on the right hand side.
However, if T(n)=6n-1, then
first term = T(1)=6(1)-1=5,
but second term T(2)=6(2)-1=11...
P=7+7+12+12P=14+24P=38
See the attachment for diagram
-1 1, -2 2, 3 -3. Is this what you wanted? If no tell me in comments and maybe a can help fix.
Answer:
x = 1, y = 1
Step-by-step explanation:
3x - 4y = -1
5x + 2y = 7
If we multiply the whole second equation by 2, we get:
10x + 4y = 14
Adding this to the first equation:
10x + 4y + 3x - 4y = 14 - 1
13x = 13
x = 1
Applying this to the second equation:
5 (1) + 2y = 7
2y = 2
y = 1
