Answer:
Ratio of Vrms of argon to Vrms of hydrogen = 0.316 : 1
Explanation:
The root-mean-square speed measures the average speed of particles in a gas, and is given by the following formula:
Vrms = 
where R is molar gas constant = 8.3145 J/K.mol, T is temperature in kelvin, M is molar mass of gas in Kg/mol
For argon, M = 40/1000 Kg/mol = 0.04 Kg/mol, T = 4T , R = R
Vrms = √(3 * R *4T)/0.04 = √300RT
For hydrogen; M = 1/1000 Kg/mol = 0.001 Kg/mol, T = T, R = R
Vrms = √(3 * R *T)/0.001 = √3000RT
Ratio of Vrms of argon to that of hydrogen = √300RT / √3000RT = 0.316
Ratio of Vrms of argon to that of hydrogen = 0.316 : 1
Answer: Water. H2O
Explanation: a chemical compound is composed of many identical molecules made from more than one element, in this case Hydrogen and Oxygen.
Answer:(d) has a high melting point because it has a giant covalent structure ... (i) Calculate the maximum mass of propyl ethanoate that can be made from 7.20 g of ethanoic ... (c) Anhydrous aluminium chloride contains 20.2% by mass of aluminium. (i) Show that the empirical formula for anhydrous aluminium chloride is A
Explanation:
Answer:
By decreasing the volume, the equilibrium will shift to the side with the smallest amount of particles
Explanation:
Step 1: Data given
The principle of Le Chatelier says:
When the volume is decreased, the equilibrium will shift to the side of the smallest number of particles.
2NOBr(g) ⇌ 2NO(g)+Br2(g)
In the following example, we have 2 moles of NOBr (on the left side) and 3 moles of gas on the right side. This means the left side, the reactant side, has the smallest number of particles.
The equilibrium will here shift to the left side, the side of NOBr.
In the following example
2NO2(g) ⇌ N2O4(g)
We have 2moles of NO2 on the left side and 1 mol of N2O4 on the right side.
By decreasing the volume, the equilibrium will shift to the side of the smallest number of moles. Here this is the right side, the side of N2O4.
