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sergiy2304 [10]
1 year ago
9

write the spontaneous net cell reaction. include physical states. net cell reaction: 2al(s) 2br {2}(l)

Chemistry
1 answer:
ElenaW [278]1 year ago
8 0

The net cell reaction is: 2Al(s) + 2Br2(l) → 4Br(s) + 2Al2O3(s)

What is a net cell reaction?

A net cell reaction is the overall chemical reaction that occurs during a redox reaction in a cell. It is the sum of all of the individual chemical reactions that take place in the cell and is usually written as an equation with the reactants on the left-hand side and the products on the right-hand side.

What is a chemical reaction?

A chemical reaction is a process in which two or more substances interact to form new substances with different chemical properties. Chemical reactions involve the breaking and forming of chemical bonds, releasing or absorbing energy, and can be either exothermic (releasing energy) or endothermic (absorbing energy).

To know more about chemical reactions,

brainly.com/question/16416932

#SPJ4

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Answer:

Sand

Explanation:

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3 years ago
The speed of Train A is 88 km/hr, and the speed of Train B is 96 km/hr. Based on this information, which of the following statem
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3 years ago
given that the speed of light is 2.998 x 108 m/s, what is the frequency of a wave that has a wavelength of 3.55 x 10-8 meters
Vesna [10]
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8 0
3 years ago
What kind of changes occur between atoms when substances undergo chemical reactions?
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8 0
3 years ago
The average rate of disappearance of ozone in the reaction 2o3(g) → 3o2(g) is found to be 7.25×10–3 atm over a certain interval
worty [1.4K]
<h3><u>Answer</u>;</h3>

1.0875 x 10-2 atm

<h3><u>Explanation;</u></h3>

2O3(g) → 3O2(g)

rate = -(1/2)∆[O3]/∆t = +(1/3)∆[O2)/∆t  

The average rate of disappearance of ozone ... is found to  

be 7.25 × 10–3 atm over a certain interval of time.

This means (ignoring time)

∆[O3]/∆t = -7.25 × 10^–3 atm  

(it is disappearing, thus the negative sign)

rate = -(1/2)∆[O3]/∆t  

rate = -(1/2)*(-7.25 × 10^–3 atm)

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rate = +(1/3)∆[O2)∆t  

3.625 × 10–3 atm = +(1/3)∆[O2)/t  

∆[O2)/∆t = (3)*(3.625× 10^–3 atm)

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4 0
3 years ago
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