GET IT RIGHT FOR BONUS

Chemistry

1 answer:

storchak [24]3 years ago

5 0

Answer:

Sand

Explanation:

with salt distillation will work, heat the solution and collect the water in a seperate beaker

With sugar you do the same, boil away the water and collect the water vapour, you'll be left with sugar in the original container and water if you collected it

Use a fraction of column and heat the solution, the alcohol will be seperated out

Sand is the only one that uses mechanical filtration

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2 years ago

Which is the correct name of a compound that is formed by Si and O?

svp [43]

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2 years ago

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Kamila [148]

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6 0

3 years ago

What is the concentration of an naoh solution that requires 15.0 ml of a 0.750 m h2so4 solution to neutralize 17.5 ml of naoh?

e-lub [12.9K]

So the first thing we must do is write a balanced equation for the reaction and we know the equation is balnced when all the species on the RHS is equal to the species on the LHS
2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

So now it's time to identify what reactant you know the most for from the question (volume & conc. of H₂SO₄) and use that info to find the unknown (conc. of NaOH)

If 1000 ml of H₂SO₄ contain 0.750 mol [0.750 M is the amount of moles in
1 L (1000 ml)]
then let 15 ml of H₂SO₄ contain x mol [15 ml is the amount of the acid that took part in the reaction]

⇒ x = $\frac{15ml * 0.750 mol}{1000 ml}$

= 0.01125 mol

Mole ratio of NaOH to H₂SO₄ can be obtained from the balanced equation
0 2NaOH + 1H₂SO₄ → Na₂SO₄ + 2H₂O

mole ratio of NaOH to H₂SO₄ is 2 : 1

∴ if mole of of H₂SO₄ = 0.01125 mol
 then moles of NaOH = (0.01125 mol) × 2
= 0.0225 mol

If 17.5 ml of NaOH contain 0.0225 mol [this was given in the question]
then let 1000 ml of NaOH contain x

⇒ x = $\frac{1000ml * 0.0225 mol}{17.5 ml}$

= 1.286 mol

∴ concentration of NaOH is 1.286 mol/L

8 0

3 years ago

If I have a 50.0 liter container that holds 45 moles of gas at a

Darina [25.2K]

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CP)X 50.L)= (45 mol)(0.0821 light_kimol)(473k)

P = 30am or 4000 kPa

5 0

3 years ago