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Airida [17]
3 years ago
8

GET IT RIGHT FOR BONUS

Chemistry
1 answer:
storchak [24]3 years ago
5 0

Answer:

Sand

Explanation:

with salt distillation will work, heat the solution and collect the water in a seperate beaker

With sugar you do the same, boil away the water and collect the water vapour, you'll be left with sugar in the original container and water if you collected it

Use a fraction of column and heat the solution, the alcohol will be seperated out

Sand is the only one that uses mechanical filtration

You might be interested in
What is the [h3o+] for a solution at 25°c that has poh = 5.640?
jonny [76]

Answer:

= 4.37*10^-9 M

Explanation:

We know that;

pH + pOH = 14

Therefore;

pH = 14 - pOH

Which means; pH = 14 - 5.64

                               = 8.36

But;

pH = -log[H3O+]

Thus;

8.36 = -log[H3O+]

[H3O+] =  10^(-8.36)

        = 4.37*10^-9 M

5 0
3 years ago
A 50.0 mL solution of 0.141 M KOH is titrated with 0.282 M HCl . Calculate the pH of the solution after the addition of each of
Kobotan [32]

Answer:

pH =1 2.84

Explanation:

First we have to start with the <u>reaction</u> between HCl and KOH:

HCl~+~KOH->~H_2O~+~KCl

Now <u>for example, we can use a volume of 10 mL of HCl</u>. So, we can calculate the moles using the <u>molarity equation</u>:

M=\frac{mol}{L}

We know that 10mL=0.01L and we have the concentration of the HCl 0.282M, when we plug the values into the equation we got:

0.282M=\frac{mol}{0.01L}

mol=0.282*0.01

mol=0.00282

We can do the same for the KOH values (50mL=0.05L and 0.141M).

0.141M=\frac{mol}{0.05L}

mol=0.141*0.05

mol=0.00705

So, we have so far <u>0.00282 mol of HCl</u> and <u>0.00705 mol of KOH</u>. If we check the reaction we have a <u>molar ratio 1:1</u>, therefore if we have 0.00282 mol of HCl we will need 0.00282 mol of KOH, so we will have an <u>excess of KOH</u>. This excess can be calculated if we <u>substract</u> the amount of moles:

0.00705-0.00282=0.00423mol~of~KOH

Now, if we want to calculate the pH value we will need a <u>concentration</u>, in this case KOH is in excess, so we have to calculate the <u>concentration of KOH</u>. For this, we already have the moles of KOH that remains left, now we need the <u>total volume</u>:

Total~volume=50mL+10mL=60mL

60mL=0.06L

Now we can calculate the concentration:

M=\frac{0.00423mol}{0.06L}

M=0.0705

Now, we can <u>calculate the pOH</u> (to calculate the pH), so:

pOH=-Log(0.0705)

pOH=1.15

Now we can <u>calculate the pH value</u>:

14=~pH~+~pOH

pH=14-1.15=12.84

8 0
3 years ago
Which of the following ions is a polyatomic ion?
nlexa [21]
Among the choices, the polyatomic ion is only the third choice, NH4+ where it is composed of nitrogen one atom of nitrogen and 4 atoms of hydrogen. Choice 2 is a monoatomic atom being composed only of calcium. Then, the first and fourth choices are not ions because they are not charged.
4 0
3 years ago
HELP!!! The chemical formula is different from the empirical formula in
Lelechka [254]

Answer:

the Ans is H2O2

Explanation:

THANKS.............

3 0
2 years ago
Read 2 more answers
Aluminum reacts with iron nitrate to form aluminum nitrate and iron. What is the
Lelechka [254]
The reactants are aluminum and iron nitrate.
5 0
2 years ago
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