3 years ago

given that the speed of light is 2.998 x 108 m/s, what is the frequency of a wave that has a wavelength of 3.55 x 10-8 meters

1 answer:

Vesna [10]3 years ago

8 0

Frequency, f = v / λ

f = 2.998 * 10⁸ / 3.55*10⁻⁸

f = 8.445 * 10¹⁵ Hz.

You might be interested in

larisa [96]

I used to know this. I don't really remember but is used to know it. Im in 6th grade now

8 0

3 years ago

Natali [406]

Answer:

Divergent plate boundary

Explanation:

7 0

3 years ago

4vir4ik [10]

Answer:

Explanation:

Relationship between wavenumber and Rydberg constant (R) is as follows:

$wave\ number=R\times Z^2\frac{1}{n_1^2} -\frac{1}{n_1^2}$

Here, Z is atomic number.

R=109677 cm^-1

Wavenumber is related with wavelength as follows:

wavenumber = 1/wavelength

wavelength = 253.4 nm

$wavenumber=\frac{1}{253.4\times 10^{-9}} \\=39463.3\ cm^{-1}$

Z fro Be = 4

$39463.3=109677\times 4^2(\frac{1}{n_1^2} -\frac{1}{5^2})\\39463.3=109677\times 16(\frac{1}{n_1^2} -\frac{1}{5^2})\\n_1=4$

Therefore, the principal quantum number corresponding to the given emission is 4.

6 0

3 years ago

valina [46]

For me the answer is E. It is composed of one Ru2+ ion and two F- ions.

6 0

3 years ago

Art [367]

Answer:

The three isomers having the molecular formula $C_{3} H_{8}O$ are drawn in the figure below.

Explanation:

5 0

2 years ago