Answer: The partial pressure of the Kr is 320 mm Hg.
Explanation:
According to Raoult's Law , the partial pressure of each component in the solution is equal to the total pressure multiplied by its mole fraction. It is mathematically expressed as
where, = partial pressure of component A
= mole fraction of A
= total pressure
mole fraction of Krypton =
Thus partial pressure of the Kr is 320 mm Hg
Answer:
The molar mass of H₂O₂ (the solute) in the aqueous solution of
H₂O₂ is 51 g
Explanation:
Given;
H₂O₂ compound
Concentration of aqueous solution of H₂O₂ = 1.5M
The molecular mass of H₂O₂ = (1 x 2) + (16 x 2) = 34 g/mol
Reacting mass (g) = Concentration x Molar mass
Reacting mass (g) = 1.5 x 34
Reacting mass (g) = 51 g
Therefore, the molar mass of H₂O₂ (the solute) in the aqueous solution of
H₂O₂ is 51 g