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Alexxandr [17]
3 years ago
10

PLEASE HELP ASAP

Chemistry
2 answers:
Pepsi [2]3 years ago
8 0

Answer:

0.25 g/cm³

Step-by-step explanation:

As we know

The density is given by

Density = Mass / Volume

Putting the values

Density = 5g / 20 cm³

Density = 0.25 g/cm³

Sorry if wrong I'm not great at math!

Dahasolnce [82]3 years ago
5 0

Answer:0,25 g/cm3 creo

Explanation:densidad es masa entre volumen

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lisov135 [29]

<u>Answer:</u>

<u>For a:</u> The chemical name and chemical formula formed is sodium nitride and Na_3N

<u>For b:</u> The chemical name and chemical formula formed is strontium oxide and SrO

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For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.  

The nomenclature of ionic compounds is given by:

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2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

  • <u>For a:</u> Sodium and nitrogen:

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To form Na^{+} ion, this element will loose 1 electron.

Nitrogen is the 7th element of periodic table having electronic configuration of [He]2s^22p^3.

To form N^{3-} ion, this element will gain 3 electrons.

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

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Strontium is the 38th element of periodic table having electronic configuration of [Kr]5s^2.

To form Sr^{2+} ion, this element will loose 2 electrons.

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To form O^{2-} ion, this element will gain 2 electrons.  

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for strontium oxide is SrO

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Aluminium is the 13th element of periodic table having electronic configuration of [Ne]3s^23p^1

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By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

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