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olchik [2.2K]
1 year ago
14

if the aud daclrck clock has a frequency of 48 khz. what value would you set the constant in the stretch timer of the button deb

ounce circuit, to get a delay of 360 ms?
Physics
1 answer:
timama [110]1 year ago
5 0

To obtain a delay of 360 ms for a clock with frequency of 48 khz, we must set the constant in the button debounce circuit's stretch timer to the value of 1720.

Set the comparator value of the debounce circuit's stretch timer to have a delay of one second to examine the impact of the pulse stretch timer. To do this, set the stretch compare megafunction's constant value to 4800

For 1 second = 48000

For 360 ms = \frac{4800}{1} × 360 × 10^{-3}

                  = 17280

Some pupils struggle with the concept of switch bounce. They are never less than amazed when we use the oscilloscope to view a switch's output. Depending on the situation, I utilize either hardware or software for the debounce solution. A capacitor and resistor are frequently inexpensive in terms of price and board area, thus I typically choose a hardware solution to free up my inexpensive microcontroller to perform other crucial tasks.

Learn more about Debounce circuit's stretch timer here:

brainly.com/question/4976423

#SPJ4

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