A container of gas is at a pressure of 1.3x10^5 Pa and a volume of 6 m^3. How much work is done by the gas if it expands at a co
1 answer:
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Answer:
7,79 seconds
Explanation:
You need to use the acceleration formula. A is acceliration, is change in velocity and t is time.
You need to multiply the formula with t and divide by a and you get
a*t=
t= /a
after that you just need to insert the numbers
change in velocity is 76.4 minus 0.
acceliration is gravitational acceleration which is 9.81.
After that you get
t=76.4/9.81
t= 7,787971458 s