You and your friend are having a discussion about weight. He claims he weighs less on the 100th floor of a building that he does
1 answer:
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Minimum diameter is required for the wire is 1.2X10⁻³m.
Tensile force, which consists of tensile stress and tensile strain, is the stretching force exerted on the material. This indicates that the forces are attempting to stretch the material that is subject to the force since it is under tension.
Given;
Tensile force (ft) = 780 N
length (l) = 3.00 mm
change in length (Δl) = 0.25 cm
determine the strain ε = Δl/l
determine the stress σ = Eε = E(Δl/l)
determine the cross-sectional area A = f/σ = ft/EΔl
determine the diameter d = 2 =
take Young's modulus for steel E=200 GPa, Substitute the values,
d = = 1.2X10⁻³
minimum diameter is required for the wire is 1.2X10⁻³m.
Learn more about the Tensile force with the help of the given link:
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I understand that the question you are looking for is "A circular steel wire 3.00 cm long must stretch no more than 0.25 cm when a tensile force of 780 N is applied to each end of the wire. What minimum diameter is required for the wire?"
Answer:
D. 10 T
Explanation:
When a particle is moving in a magnetic field, the magnetic force provides the centripetal force that keeps the particle in circular motion.
The cyclotron period (the period the particle takes to complete one orbit) can be found to be
where
m is the mass of the particle
q is its charge
B is the magnetic field
As we see, the period is directly proportional to the mass of the particle.
In this problem, the second particle is ten times as massive as the first one:
m' = 10 m
while the speed is the same. So, the period of the second particle is