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1 year ago

12

PLEASE HELP ME!!! WILL GIVE YOU A FOLLOW

1 answer:

Dvinal [7]1 year ago

5 0

4/10^2 = 0.04
which is equal to:
4x10^-2
As there are two digits behind the decimal point up to( and including the 4) thus the 10^-2
And as the digit is a 4 you multiply 10^-2 by 4

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Which transformations will alter the location of the vertex?

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Answer:

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3 years ago

Please help me with this question

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3 years ago

Evaluate the expression 4+−4√2+−1√ and write the result in the form a+bi.

castortr0y [4]

In the expression, the real number a equals 12 and the real number b equals -16.

<h3>How to explain the information?</h3>

It should be noted that the expression given is:

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Therefore, we need to expand the expression. This will be:

= (4 - 2i)(4 - 2i)

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Evaluate the expression ( 4 − 2 i )² and write the result in the form a + b i.

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2 years ago

Using the given information, give the vertex form equation of each parabola.

Amanda [17]

Answer:

The equation of parabola is given by : $(x-4) = \frac{-1}{3}(y+3)^{2}$

Step-by-step explanation:

Given that vertex and focus of parabola are

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Focus:( $\frac{47}{12}$ ,-3)

The general equation of parabola is given by.

$(x-h)^{2} = 4p(y-k)$ , When x-componet of focus and Vertex is same

$(x-h) = 4p(y-k)^{2}$ , When y-componet of focus and Vertex is same

where Vertex: (h,k)

and p is distance between vertex and focus

The distance between two points is given by :

L= $\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2}}$

For value of p:

p= $\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2}}$

p= $\sqrt{(4-\frac{47}{12})^{2}+((-3)-(-3))^{2}}$

p= $\sqrt{(\frac{1}{12})^{2}}$

p= $\frac{1}{12}$ and p= $\frac{-1}{12}$

Since, Focus is left side of the vertex,

p= $\frac{-1}{12}$ is required value

Replacing value in general equation of parabola,

Vertex: (h,k)=(4,-3)

p= $\frac{-1}{12}$

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Step-by-step explanation:

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