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kvasek [131]
3 years ago
11

"Given the acceleration of an object as a function of time, what additional information is necessary to use integration to deter

mine the velocity of the object as a function of time______________.
Physics
1 answer:
Elena L [17]3 years ago
5 0

Answer:

Explanation:

acceleration is defined as the rate of change of velocity.

a = dv/dt

dv = a dt

So, integrate it with respect to time. Here we need the value of initial velocity that means at t = 0, v = ? to find the value of velocity.  

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Pls reply... plss!! help me​
viktelen [127]

Answer:

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Explanation:

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7 0
3 years ago
A student standing on the ground throws a ball straight up. The ball leaves the student's hand with a speed of 19.0 m/s when the
german

Answer: 4 s

Explanation:

Given

The ball leaves the hand of student with a speed of u=19\ m/s

When the hand is h=2.5\ m above the ground

Using the equation of motion we can write

h=ut+\dfrac{1}{2}at^2

Substitute the values

\Rightarrow 2.5=-19t+0.5\times 9.8t^2\\\Rightarrow 4.9t^2-19t-2.5=0\\\\\Rightarrow t=\dfrac{19\pm \sqrt{(-19)^2-4\times 4.9\times (-2.5)}}{2\times 19}\\\Rightarrow t=4.0049\quad [\text{Neglecting the negative value of }t]

Thus, the ball will take 4 s to hit the ground.

5 0
3 years ago
Superconductors have no measurable resistance. true or false?
trapecia [35]
True, they have zero electrical resistance.
7 0
3 years ago
A 250 kg flatcar 25 m long is moving with a speed of 3.0 m/s along horizontal frictionless rails. A 61 kg worker starts walking
Anna11 [10]

Answer:

x=31.09m

Explanation:

p1=p2

The momentum of flatcar and the momentum of the worker so

The velocity of the worker is:

m_{f}*v_{f}=m_{w}*v_{w}\\\\v_{f}=\frac{m_{f}*v_{f}}{m_{w}}\\v_{f}=\frac{61kg*3.0\frac{m}{s}}{250kg}\\v_{f}=0.732\frac{m}{s}

The total motion has a total velocity and is

Vt=v_{w}+v_{f}\\Vt=0.732\frac{m}{s}+3.0\frac{m}{s}\\Vt=3.732\frac{m}{s}

The time the worker take walking is

t=\frac{x}{v_{w}}\\t=\frac{25m}{3\frac{m}{s}}=8.33s

Now the total time and the total velocity determinate the motion of tha flatcar how far has moved

x=t*Vt\\x=8.33s*3.732\frac{m}{s} \\x=31.09m

5 0
3 years ago
Calculate the amount of air in a room 6m long, 5m wide and 3mm high.​
sattari [20]

Answer:

0.09kg of air

Explanation:

The dimensions of the room are given

change the height to meters by dividing it by thousand.

For the volume multiplying the length,width and height (all should be in the same unit most suitable being meters).

Volume refers to the amount of space inside a box or a object.

The amount of air is equal to the volume.

6 0
2 years ago
Read 2 more answers
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