"1.<span> characterized by order and planning</span>
2.<span> not haphazard"
is the answers i found in the dictionary </span>
Result of the other variable
Answer:
The solution for this problem is:
We will be using the formula for force which is F = ma
=>10,000 = 2000 * a
but we need to solve for acceleration so divide both sides by 2000, we will get:
=>a = 5 m/s^2
Let the initial velocity was u m/s
=>By v = u - at
=>0 = u - 5 x 6
Since acceleration is constant the velocity can be computed by multiplying the acceleration by 6 seconds.
=>u = 30 m/s
Explanation:
The period of any wave is the time it takes for its angle
to go from zero to 2pi .
The 'sin' function is a wave. The angle of this one is (8pi t).
When t=0, the angle is zero.
Wonderful.
Now, how long does it take for the angle to grow to 2pi ?
I*n other words, when is (8pi t) = 2pi ?
Divide each side by '2pi': . . . . . 4 t = 1
Divide each side by ' 4 ': . . . . . t = 1/4
And there you are. Every time 't' grows by 1/4, (8pi t) grows by 2pi.
So if you graph this simple harmonic motion described by 'd', you'll
see the graph wiggle up and down with a period of 1/4 .
Answer:
we see it is a linear relationship.
Explanation:
The magnetic flux is u solenoid is
B = μ₀ N/L I
where N is the number of loops, L the length and I the current
By applying this expression to our case we have that the current is the same in all cases and we can assume the constant length. Consequently we see that the magnitude of the magnetic field decreases with the number of loops
B = (μ₀ I / L) N
the amount between paracentesis constant, in the case of 4 loop the field is worth
B = cte 4
N B
4 4 cte
3 3 cte
2 2 cte
1 1 cte
as we see it is a linear relationship.
In addition, this effect for such a small number of turns the direction of the field that is parallel to the normal of the lines will oscillate,
