Question

Light of frequency 3.62 x 1015 Hz

Answer 1

The kinetic energy that the liberated electron has in eV based on the given values is :

10.28 eV.

Explanation:

• 1 eV is the kinetic energy gained by an electron or proton when acted upon by a 1 volt potential difference. E = QV is the formula for energy in terms of charge and potential difference.

A photoelectron's maximum kinetic energy is given by

                     Emax = hf - W

• where h is Plank's constant,

• f is the incident photon's frequency, and

• W denotes the metal surface's work function.

here given,

f = 3.62 x 10¹⁵ Hz

W = 4.70 eV

 by recalling the equation for a photoelectron's maximum kinetic energy with given values,

  Emax = hf - W

             = ((4.14 × 10⁻¹⁵eV.s)(3.62 x 10¹⁵ Hz)) - (4.70 eV)

             = 10.28 eV

As a result, we discovered that the maximum kinetic energy of electrons is 10.28eV.

To learn more about kinetic energy of electrons refer to :

brainly.com/question/21208918

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