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Soloha48 [4]
3 years ago
11

A substance with a density of 2.70 g/mL occupies a volume of 21.3 mL. What is the mass of the sample? Report your answer in unit

s of mg. Use significant figures. Do not enter “mg” as part of your answer. Do not use scientific notation.
Chemistry
1 answer:
katen-ka-za [31]3 years ago
7 0
We know the formula of the density:
ρ =\frac{m}{V} ;
So the mass will be equal to:
m = ρ * V = 2.70  * 21.3 = 57,51 g = 57510 mg of substance.
So the answer is 57510.
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What else is produced during the combustion of butane, C4H10?<br><br> 2C4H10 + 13O2 → <br> + 10H2O
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<h3>Answer:</h3>

8CO₂

<h3>Explanation:</h3>

We are given;

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We are required to determine the other product produced in the combustion of butane apart from water.

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alexdok [17]

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ΔTb=iKbm

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i for CaCO3= 2

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m=Molality of CaCO₃:

Molality of CaCO₃=Number of moles of CaCO₃/ Mass of solvent (Kg)

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ΔTb=iKbm

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=14.65 °C

boiling point of a solution can be calculated:

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14.65=Tb (solution)-118.1

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