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RSB [31]
3 years ago
15

What is the relationship between anabolic and catabolic pathways?

Chemistry
1 answer:
BartSMP [9]3 years ago
7 0

Explanation:

Anabolic pathways are those that require energy to synthesize larger molecules. Catabolic pathways are those that generate energy by breaking down larger molecules. Both types of pathways are required for maintaining the cell's energy balance.

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Pleaseeeeeee hlepThe half-life of cobalt-60 is 5.26 years. After 10.52 years, 5 grams of a 20-gram sample will remain.
vladimir1956 [14]

The half-life of cobalt-60 is 5.26 years. After 10.52 years, 5 grams of a 20-gram sample will remain is TRUE

<u>Explanation:</u>

Mass of cobalt = 20 g  

Half-life = 5.26 years  

Mass remains after 10.52 years = 5 g  

This can be solved by using given below formula, m(t)=m_{o}\left(\frac{1}{2}\right)^{\frac{l}{5.26}}

m_{0} = initial mass  

t = number of years from when the mass was m_0  

m(t) = remaining mass after t years  

Number of half-lives = \frac{\text { Time elapsed }}{\text { Half -life }}

Number of half-lives = \frac{10.52 \text { years }}{5.26 \text { years }}

Number of half-lives = 2  

At time zero = 20 g  

At first half-life = \frac{20\ g}{2}  = 10 g  

At second half life = \frac{10\g}{2} = 5 g  

The given statement is true.

4 0
3 years ago
The heat of vaporization of 1–pentanol is 55.5 kJ/mol, and its entropy of vaporization is 148 J/K•mol. What is the approximate b
tensa zangetsu [6.8K]

Answer:

375 K

Explanation:

Using the experssion shown below as:

\Delta G^0=\Delta H^0_{vap}-T\Delta S^0_{vap}

At vaporization point, the liquid and the gaseous phase is in the equilibrium.

Thus,

\Delta G^0=0

So,

Delta H^0_{vap}=T\Delta S^0_{vap}

Given that:

Delta H^0_{vap}=55.5\ kJ/mol

Also, 1 kJ = 10³ J

So,

Delta H^0_{vap}=55500\ J/mol

\Delta S^0_{vap}=148\ J/K.mol

So, temperature is :

T=\frac{Delta H^0_{vap}}{\Delta S^0_{vap}}

T=\frac{55500}{148}

<u>T= 375 K</u>

3 0
3 years ago
The microwaves in an oven are of a specific frequency that will heat the water molecules contained in food. (This is why most pl
statuscvo [17]

Answer:

2E-24

Explanation:

8 0
3 years ago
Calculate the value deltaG°​
atroni [7]

Answer:

ΔG=ΔG0+RTlnQ where Q is the ratio of concentrations (or activities) of the products divided by the reactants. Under standard conditions Q=1 and ΔG=ΔG0 . Under equilibrium conditions, Q=K and ΔG=0 so ΔG0=−RTlnK . Then calculate the ΔH and ΔS for the reaction and the rest of the procedure is unchanged.

Explanation:

4 0
3 years ago
_H2+O2=_H2O<br> balance help please
erastovalidia [21]
Both are 2
2H2+O2=2H2O
5 0
3 years ago
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