1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
RSB [31]
3 years ago
15

What is the relationship between anabolic and catabolic pathways?

Chemistry
1 answer:
BartSMP [9]3 years ago
7 0

Explanation:

Anabolic pathways are those that require energy to synthesize larger molecules. Catabolic pathways are those that generate energy by breaking down larger molecules. Both types of pathways are required for maintaining the cell's energy balance.

You might be interested in
Two raw materials used in manufacturing of indenouse soap
Trava [24]

Answer:Naoh and animal fats

Explanation:

Also perfume along with ones desire

Feel pleasure to help u

8 0
3 years ago
A military jet cruising at an altitude of 12.0kmand speed of 1900./kmh burns fuel at the rate of 74.4/Lmin. How would you calcul
anygoal [31]

Answer: amount = 2466.95L

Explanation:

given that the speed is = 1900./kmh i.e. 1hr/900km

distance = 1050km

the fuel burns at a rate of 74.4 L/min

therefore the amount of fuel that the jet consumes on a 1050.km becomes;

total fuel used = time × fuel burning rate

where time = distance / speed

∴ total fuel used (consumed) = time × fuel burning rate

total fuel consumed = (1050km × 1hr/1900km) × (60min/ 1hr × 74.4L/1min)

total fuel consumed = 2466.95L

6 0
3 years ago
A container of oxygen has a volume of 30.0 mL and a pressure of 72.5 psi. If the pressure of the oxygen gas is reduced to 28 psi
OLga [1]

Answer:

THE NEW VOLUME OF THE OXYGEN GAS AT 28 PSI FROM 72.5 PSI IS 0.078 L.

Explanation:

Initial volume of the oxygen in the container = 30.0 mL = 30 / 000 L = 0.03 L

Initial pressure of the oxygen = 72.5 psi =  1 psi = 6890 pascal

Final pressure = 28 psi

Final volume = unknown

First convert the mL to L and since both pressures are in similar unit that is psi; there is no need converting them to pascal or other standard unit of pressure. They cancel each other out.

This question follows Boyle's equation of gas laws and mathematically it is written as:

P1 V1 = P2 V2

Re-arranging by making P2 the subject of the formula, we have:

V2 = P1 V1 / P2

V2 = 72,5 * 0.03 / 28

V2 = 2.175 /28

V2 = 0.0776 L

The new volume of the oxygen gas at a change in pressure from 72.5 psi to 28 psi is 0.078 L.

8 0
3 years ago
The nucleus of the cell
Stells [14]

Answer:

c

Explanation:

it is c because that is the andwer

3 0
3 years ago
HELP WITH CHEMISTRY PLEASE!
maria [59]

Answer:

1) 1.52 atm.

2) 647.85 K.

3) 20.56 L.

4) 1.513 mole.

5) 254.22 K = -18.77 °C.

Explanation:

  • In all this points, we should use the law of ideal gas to solve this problem: PV = nRT.
  • Where, P is the pressure (atm), V is the volume (L), n is the number of moles, R is the general gas constant (0.082 L.atm/mol.K), and T is the temperature (K).

1) In this point; n, R, and T are constants and the variables are P and V.

P and V are inversely proportional to each other that if we have two cases we get: P1V1 = P2V2.

<u><em>In our problem:</em></u>

P1 = ??? <em>(is needed to be calculated) </em>and V1 = 45.0 L.

P2 = 5.7 atm and V2 = 12.0 L.

Then, the original pressure (P1) = P2V2 / V1 = (5.7 atm x 12.0 L) / (45.0 L) = 1.52 atm.


2) In this case, n and R are the constants and the variables are P, V, and T.

P and V are inversely proportional to each other and both of them are directly proportional to the temperature of the gas that if we have two cases we get: P1V1T2 = P2V2T1.

<u><em>In our problem:</em></u>

P1 = 212.0 kPa, V1 = 32.0 L, and T1 = 20.0 °C = (20 °C + 273) = 293 K.

P2 = 300.0 kPa, V2= 50.0 L, and T2 = ??? <em>(is needed to be calculated) </em>

Then, the temperature in the second case (T2) = P2V2T1 / P1V1 = (300.0 kPa x 50.0 L x 293 K) / (212.0 kPa x 32.0 L) = 647.85 K.


3) In this case, P, n and R are the constants and the variables are V, and T.

V and T are directly proportional to each other that if we have two cases we get: V1T2 = V2T1.

<u><em>In our problem:</em></u>

V1 = 25.0 L and T1 = 65.0 °C + 273 = 338 K.

V2 = ??? <em>(is needed to be calculated) </em> and T2 = 5.0 °C + 273 = 278 K.

Herein, there is no necessary to convert T into K.

Then, the volume in the second case (V2) = V1T2 / T1 = (25.0 L x 278 °C) / (338 °C) = 20.56 L.


4) We can get the number of moles that will fill the container from: n = PV/RT.

P = 250.0 kPa, we must convert the unit from kPa to atm; <em><u>101.325 kPa = 1.0 atm</u></em>, then P = (1.0 atm x 250.0 kPa) / (101.325 kPa) = 2.467 atm.

V = 16.0 L.

R = 0.082 L.atm/mol.K.

T = 45 °C + 273 = 318 K.

Now, n = PV/RT = (2.467 atm x 16.0 L) / (0.082 L.atm/mol.K x 318 K) = 1.513 mole.


5) In this case, V, n and R are the constants and the variables are P, and T.

P and T are directly proportional to each other that if we have two cases we get: P1T2 = P2T1.

<u><em>In our problem:</em></u>

P1 = 2200.0 mmHg and T1 = ??? <em>(is needed to be calculated) </em>.

P2 = 2700.0 mmHg and T2 = 39.0 °C + 273 = 312.0 K.

Herein, there is no necessary to convert P into atm.

Then, the temperature in the morning (T1) = P1T2 / P2 = (2200.0 mmHg x 312.0 K) / (2700.0 mmHg) = 254.22 K = -18.77 °C.

6 0
3 years ago
Read 2 more answers
Other questions:
  • A sample of gas has a volume of 2.4 L and a pressure of 1.2 atm. What would the pressure of the same gas sample be if the volume
    6·1 answer
  • Punnett Squares represent the probability of traits in offspring as a result of what type of
    14·2 answers
  • PLEASE HELP!!
    12·2 answers
  • What are the five characteristics of a mineral
    10·1 answer
  • The following is a chemical reaction for _______ with ozone.
    10·2 answers
  • PLEASE HELP FELLOW BRAINLIEST I NEED YOU AND QUICK!!!!!!!!!!!!!!!!!!!!!!!! Thomas Jefferson was the first to suggest what practi
    13·2 answers
  • What is not a resource of the ocean?
    7·2 answers
  • . For the reaction 2HNO3 + Mg(OH), → Mg(NO3)2 + 2H20, how many grams of magnesium nitrate are produced from 8.00 mol of nitric a
    12·1 answer
  • How many liters of water can be made from 55.0 grams of oxygen gas and an excess of
    7·1 answer
  • Given the following equation:
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!