Question

What is the zero of function f?f(x)=3 square root of x+3 -6

Answer 1

Solution:

Given:

$f(x)=3\sqrt{x+3}-6$

The zeros of a function are the values of x when f(x) is equal to 0.

Hence,

$\begin{gathered} 0=3\sqrt{x+3}-6 \\ \\ Collecting\text{ the like terms,} \\ 0+6=3\sqrt{x+3} \\ 6=3\sqrt{x+3} \\ \\ Divide\text{ both sides by 3;} \\ \frac{6}{3}=\sqrt{x+3} \\ 2=\sqrt{x+3} \\ \\ Taking\text{ the square of both sides;} \\ 2^2=x+3 \\ 4=x+3 \\ \\ Collecting\text{ the like terms;} \\ 4-3=x \\ 1=x \\ x=1 \end{gathered}$

Therefore, x = 1

The correct answer is OPTION A.