Answer:
Newton's third law is: For every action, there is an equal and opposite reaction.
Explanation:
The statement means that in every interaction, there is a pair of forces acting on the two interacting objects. The size of the forces on the first object equals the size of the force on the second object.
The magnitude of the charge on the balloon is 1.6 x 10⁻¹² C.
<h3>
What is the magnitude of the charge on the ball?</h3>
The magnitude of the charge on the ball is calculated by determining the total charge equivalent to the given number of electrons.
The charge of one electron = 1.6 x 10⁻¹⁹ Coulombs
Now, we are going to estimated the total charge of 1 x 10⁷ electrons.
1 electron = 1.6 x 10⁻¹⁹ C
1 x 10⁷ electrons = ?
= (1 x 10⁷ electrons x 1.6 x 10⁻¹⁹ C) / (1 electron)
= 1.6 x 10⁻¹² C
Thus, the total charge of 1 x 10⁷ electrons is obtained by multiplying the magnitude of charge of one electron to the entire given electrons.
Learn more about charge of electron here: brainly.com/question/9317875
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Explanation:
It is given that,
Mass of golf club, m₁ = 210 g = 0.21 kg
Initial velocity of golf club, u₁ = 56 m/s
Mass of another golf ball which is at rest, m₂ = 46 g = 0.046 kg
After the collision, the club head travels (in the same direction) at 42 m/s. We need to find the speed of the golf ball just after impact. Let it is v.
Initial momentum of golf ball, 
After the collision, final momentum 
Using the conservation of momentum as :
v = 63.91 m/s
So, the speed of the golf ball just after impact is 63.91 m/s. Hence, this is the required solution.
Answer:
0.72 Hz minimum frequency
Explanation:
When the damping is negligible,Amplitude is given as
here 
= (6.30)/(0.135) = 46.67 N/m kg
= 1.70/(0.135)(0.480) = 26.2 N/m kg
From the above equation , rearranging for ω,
⇒ ω² =46.67 ± 26.2 = 72.87 or 20.47
⇒ ω = 8.53 or 4.52 rad/s
Frequency = f
ω=2 π f
⇒ f = ω / 2π = 8.53 /6.28 or 4.52 / 6.28 = 1.36 Hz or 0.72 Hz
The lower frequency is 0.72 Hz and higher is 1.36 Hz
Place the next vector with its tail at the previous vector's head. ... To subtract vectors, proceed as if adding the two vectors, but flip the vector to be subtracted across the axes and then join it tail to head as if adding. Adding or subtracting any number of vectors yields a resultant vector.
Explanation:
