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1 year ago

Why is simple harmonic motion a fundamental for understanding physics

1 answer:

6 0

The simple harmonic motion not only describes circular movements, also describes waves motion. This makes it fundamental for physics, make us understand waves like sound or light which explains an enormus part of our environment

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If a stone dropped into a well reaches the water's surface after 3.0 seconds, how far did the stone drop before hitting the wate

Ulleksa [173]

<span>s= 0.5 at^2
</span>
0.5 x 9.81 x 3^2 = 44m

8 0

3 years ago

Read 2 more answers

A skier moving at 4.75 m/s encounters a long, rough, horizontal patch of snow having a coefficient of kinetic friction of 0.220

disa [49]

First we need to find the acceleration of the skier on the rough patch of snow.
We are only concerned with the horizontal direction, since the skier is moving in this direction, so we can neglect forces that do not act in this direction. So we have only one horizontal force acting on the skier: the frictional force, $\mu m g$ . For Newton's second law, the resultant of the forces acting on the skier must be equal to ma (mass per acceleration), so we can write:
$ma=-\mu m g$
Where the negative sign is due to the fact the friction is directed against the motion of the skier.
Simplifying and solving, we find the value of the acceleration:
$a=-(0.220)(9.81 m/s^2)=-2.16 m/s^2$

Now we can use the following relationship to find the distance covered by the skier before stopping, S:
$2aS=v_f^2-v_i^2$
where $v_f=0$ is the final speed of the skier and $v_i=4.75 m/s$ is the initial speed. Substituting numbers, we find:
$S=- \frac{v_i^2}{2a}=- \frac{(4.75 m/s)^2}{2(-2.16 m/s^2)}=5.23 m$

5 0

3 years ago

Behavior is a product of both the situation and the person. Which of the following is an example of a situation that might influ

Montano1993 [528]

Self productive and it depends on how whom is behaving.

7 0

3 years ago

Pls answer 50 points for an answer!!!!

lyudmila [28]

ummmn hi i dont know lol

5 0

2 years ago

A 3 mm inside diameter tube is placed in a fluid with a surface tension of 600 mN/m and density of 3.7 g/cm3. The contact angle

Aleks04 [339]

Answer: The height of the fluid rise is 0.01m

Explanation:

Using the equation

h = (2TcosѲ )/rpg

h= height of the fluid rise

diameter of the tube =3mm

radius of the tube= 3/2 =1.5mm=0.0015

T= surface tension = 600mN/m=0.6N/m

Ѳ = contact angle = $60^o$ C

p= density =3.7g/cm3= 3700kg/m3

g= acceleration due to gravity =9.8m/s2

h = ( 2*0.6*0.5)/(0.0015*3700*9.8)

h = 0.6/54.39

h= 0.01m

Therefore,the height of the fluid rise is 0.01m

8 0

3 years ago