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Sedaia [141]
3 years ago
14

a force is applied to a block causing it to accelerate along a horizontal, frictionless surfaces. the energy gained by the block

is equal to the
Physics
1 answer:
GaryK [48]3 years ago
3 0
Energy given to the block
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An egg is cracked/broken. Is this egg experiencing a Physical or Chemical change? (Hint: is it still an egg?)
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A boat takes 3.0 hours to travel 50 km down a river, then 5.4 hours to return. Determine the speed of the water in the river.
Nutka1998 [239]

Answer:

3.7 km/h

Explanation:

Let's call v the proper speed of the boat and v' the speed of the water in the river.

When the boat travels in the direction of the current, the speed of the boat is:

v + v'

And it covers 50 km in 3 h, so we can write

v+v' = \frac{50 km}{3 h}=16.7 km/h (1)

When the boat travels in the opposite direction, the speed of the boat is

v - v'

And it covers 50 km in 5.4 h, so

v-v'=\frac{50 km}{5.4 h}=9.3 km/h (2)

So we have a system of two equations: by solving them simultaneously, we find the value of v and v':

v+v'=16.7 \\v-v'=9.3

Subtracting the second equation from the first one we get:

(v+v')-(v-v')=16.7-9.3\\2v'=7.4\\v'=3.7

So, the speed of the water is 3.7 km/h.


5 0
3 years ago
THE ELECTROMAGNET SPECTRUM ONLY HAS WHICH SHAPE OF WAVE?
brilliants [131]

Answer: Transverse

Explanation: Transverse waves possess a vertical wave motion and a horizontal particle motion.

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3 years ago
Match the correct term with the statement that is true about it
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3 years ago
Steam at 100°C is condensed into a 38.0 g aluminum calorimeter cup containing 280 g of water at 25.0°C. Determine the amount of
KonstantinChe [14]

Answer:

7.2g

Explanation:

From the expression of latent heat of steam, we have

Heat supplied by steam = Heat gain water + Heat gain by calorimeter

mathematically,

m_{s}c_{w} \alpha _{w} + m_{s}l=m_{w}c_{w} \alpha _{w} +m_{c}c_{c} \alpha c_{c}

L=specific latent heat of water(steam)=2268J/g

c_{w}=specific heat capacity=4.2J/gK

c_{c}=specific heat capacity of calorimeter =0.9J/gk

m_{w}=280g

m_{c}=38g

α=change in temperature

\alpha _{c}=(40-25)=15

\alpha _{w}=(40-25)=15

\alpha _{s}=(100-40)=60

Note: the temperature of the calorimeter is the temperature of it content.

From the equation, we can make m_{s} the subject of formula

m_{s}=\frac{m_{w}c_{w} \alpha +m_{c}c_{c}\alpha}{c_{w}\alpha +l}

Hence

m_{s}=\frac{(280*4.2*15) +(38*0.9*15)}{(4.2*60) +2268} \\m_{s}=\frac{18153}{2520}\\ m_{s}=7.2g

Hence the amount of steam needed is 7.2g

6 0
3 years ago
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