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anzhelika [568]
3 years ago
9

Spot welding is used to fuse two sheets of metal together at one small spot. Two copper electrodes pinch the sheets together at

a point and then run a huge electric current through that point. The two sheets melt and flow together to form a spot weld. Why does this technique work only with relatively poor conductors of electricity such as stainless steel and not with excellent conductors such as copper?
Physics
1 answer:
hjlf3 years ago
7 0

Answer:

The power deposited in a metal is proportional to its electric resistance, so high-resistance metals heat more.

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? Question
Harrizon [31]

No Solution:

4x+10y = 40

2x + 5y = 40

2x - 8y=17

x - 4y = 7

One Solution:

2y - X= 12

2y - 2x =10

x + 10y =50

2x + 10y =90

Infinitely Many Solutions:

x + 2y = 1

3x + 6y= 3

2y - 3x = 5

2/5y -3/5x =1

Explanation: You only had 11 equations listed. But I believe these are the ones you want. I took the test and got them right. Hope it helps

3 0
3 years ago
The rotation period for Venus is___days. (pls help!)<br> 365<br> 186<br> 512<br> 243
sattari [20]

Answer:

243 days

Explanation:

6 0
3 years ago
Read 2 more answers
what chemical change occurs when a movie reactive substance replaces a less reactive substance in a compound
babymother [125]

yo saber esta uno h20 tomo la agua

6 0
3 years ago
A 65.0 kg skier is moving at 6.85 m/s on a frictionless, horizontal snow-covered plateau when she encounters a rough patch 4.00
marusya05 [52]

Answer:

v = 4.58 m/s

Explanation:

In order to calculate the speed of the skier when she gets the bottom of the hill, you have to calculate the speed of the skier when she crosses the rough patch.

To calculate the velocity at the final of the rough patch you take into account that the work done by the friction surface is equal to the change in the kinetic energy of the skier:

W_f=\Delta K\\\\-N\mu_kd=\frac{1}{2}mv^2-\frac{1}{2}mv_o^2=\frac{1}{2}m(v^2-v_o^2)        (1)

Where the minus sign means that the work is against the motion of the skier.

Wf: friction force

m: mass of the skier = 65.0kg

N: normal force = mg

g: gravitational acceleration = 9.8m/s^2

d: distance of the rough patch = 4.00m

v: speed at the end of the rough patch = ?

vo: initial speed of the skier = 6.85m/s

μk: coefficient of kinetic friction = 0.330

You replace the expression for the normal force in the equation (1), and solve for v:

-mg\mu_kd=\frac{1}{2}m(v^2-v_o^2)\\\\-g\mu_kd=\frac{1}{2}(v^2-v_o^2)\\\\v=\sqrt{-2g\mu_kd+v_o^2}\\\\v=\sqrt{-2(9.8m/s^2)(0.330)(4.00m)+(6.85m/s)^2}=8.53\frac{m}{s}=4.58\frac{m}{s}

Then, the speed fot he skier at the bottom of the hill is 4.58m/s

3 0
4 years ago
Can someone help me?!!!!!
SOVA2 [1]

Answer:magnitude -5; angle 160°

Explanation:

Vector A is described as having magnitude 5 and angle -20°.

To get an equivalent vector, we either leave the magnitude at 5 and add 360° to the angle, or we reverse the magnitude to -5 and add 180° to the angle.

5 @ -20° = 5 @ 340°

5 @ -20° = -5 @ 160°

The third one is the answer.

8 0
4 years ago
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