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allochka39001 [22]
3 years ago
13

A 3 mm inside diameter tube is placed in a fluid with a surface tension of 600 mN/m and density of 3.7 g/cm3. The contact angle

is measured as 60o below the horizontal. How high will the fluid rise in the tube?
Physics
1 answer:
Aleks04 [339]3 years ago
8 0

Answer: The height of the fluid rise is 0.01m

Explanation:

Using the equation

h = (2TcosѲ )/rpg

h= height of the fluid rise

diameter of the tube =3mm

radius of the tube= 3/2 =1.5mm=0.0015

T= surface tension = 600mN/m=0.6N/m

Ѳ = contact angle = 60^oC

p= density =3.7g/cm3= 3700kg/m3

g= acceleration due to gravity =9.8m/s2

h = ( 2*0.6*0.5)/(0.0015*3700*9.8)

h = 0.6/54.39

h= 0.01m

Therefore,the height of the fluid rise is 0.01m

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Find<br>the equevalent unit<br>for Ohm using<br>the<br>geren<br>formula.<br>늘​
Brut [27]

Answer:

V/A

Explanation:

Resistance equals voltage divided by current. You already know resistance's unit is the Ohm. Voltage's unit is the Volt and current's is ths Ampere. Now you can do something like this:

1Ω=\frac{1V}{1A} ⇔

Ω=V/A

Hope this helped :)

7 0
3 years ago
PLEASE HELPP<br> Look at the picture
denis23 [38]
Answer: It’s c
explaining: i guessed
8 0
3 years ago
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An object moving at a constant speed in a circle is _____.
nordsb [41]

Answer:

A. accelerating

Explanation:

Acceleration is defined as the ratio between the change in velocity and the time taken for the velocity to change:

a=\frac{\Delta v}{\Delta t}

We must note that the velocity is a vector - so it has both a magnitude (the speed) and a direction.

This means that a non-zero acceleration occurs when:

- the speed changes, or

- the direction changes, or

- both the speed and the direction change

For an object moving at constant speed in a circle, the direction changes, so the object is accelerating.

5 0
3 years ago
A helicopter is hovering above the ground. Jim reaches out of the copter (with a safety harness on) at 180 m above the ground. A
vesna_86 [32]

Answer:

The maximum height of the package is 140 m above the ground. Jim Bond will not catch the package.

Explanation:

Hi there!

The equation of height and velocity of the package are the following:

h = h0 + v0 · t + 1/2 · g · t²

v = v0 + g · t

Where:

h = height of the package at time t.

h0 = initial height.

v0 = initial velocity.

t = time.

g = acceleration due to gravity (-9.81 m/s² because we consider the upward direction as positive).

v = velocity of the package at a time t.

First, let´s find the time it takes the package to reach the maximum height. For this, we will use the equation of velocity because we know that at the maximum height, the velocity of the package is zero. So, we have to find the time at which v = 0:

v = v0 + g · t

0 = 50.5 m/s - 9.8 m/s² · t

Solving for t:

-50.5 m/s / -9.81 m/s² = t

t = 5.15 s

Now, let´s find the height that the package reaches in that time using the equation of height. Let´s place the origin of the frame of reference on the ground so that the initial position of the package is 10 m above the ground:

h = h0 + v0 · t + 1/2 · g · t²

h = 10 m + 50.5 m/s · 5.15 s - 1/2 · 9.81 m/s² · (5.15 s)²

h = 140 m

The maximum height of the package is 140 m above the ground. Jim Bond will not catch the package.

6 0
3 years ago
a 5.5 kg box is pushed across the lunch table.the net force applied to the box is 9.7 N.what is the acceleration of the box?
skelet666 [1.2K]

Answer:

1.76m/s²

Explanation:

Acceleration is the time rate of change in velocity of a body. It is a vector quantity that is it has both magnitude and direction

From newton's second law of motion which states that the rate of change of momentum of a body is proportional to the applied force which takes place in the direction of force applied.

This law gives a formula which relate force, mass and acceleration.

Force = mass x acceleration

Given that force = 9.7N , mass = 5.5kg

Since force(F)= mass(m) x acceleration(a)

Therefore F = ma

Divide both sides by m

F/m = ma/m

Therefore,

Acceleration (a)  = F/m

Acceleration = 9.7N ➗ 5.5kg

Acceleration = 1.76m/s²

The S. I unit of acceleration is m/s²

I hope this was helpful, Please mark as brainliest  

5 0
3 years ago
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