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Anton [14]
1 year ago
5

Calculate the grams of so2 gas present at stp in a 5. 9 l container. (atomic weights: s=32, o=16).

Chemistry
1 answer:
Solnce55 [7]1 year ago
8 0

The 5.9 L container at STP contains 16.83 g of SO2.

To begin, we must determine how many moles of SO2 are contained in the 5.9 L container.

At standard temperature and pressure (STP), one mole of SO2 equates to 22.4 liters.

5.9 L = 5.9 / 22.45.9 L = 0.26 moles of SO2 as a result.

The result is that 0.263 moles of SO2 are present in the container.

Following that, we shall determine the mass of 0.263 moles of SO2.

The following are ways to do this:

The mass of SO2 is 32 + (16 2) = 32 + 32= 64 g/mol,

where SO2 Mole = 0.263 Molar.

Molar + Molar Mass Equals Mass

SO2 mass is 16.83 g, or 0.263 of a kilogram.

Therefore, 16.83 g of SO2 are present in the 5.9 L container at STP.

to know more about mass, visit to:-

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A. Wipe down the glassware to remove any cleaning solvent.

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what volume of a 0.138 m potassium hydroxide solution is required to neutralize 26.0 ml of a 0.205 m nitric acid solution?
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A neutralization titration is a chemical response this is used to decide the composition of an answer and what kind of acid or base is in it. This is a way of volumetric analysis and the formula is (M1V1 = M2V2).

Utilize the titration method of M1V1 = M2V2 in view that we're given the concentrations of every compound and the quantity of KOH. Let: M1 = 0.138M, V1 = x, M2 = 0.205M, V2 = 26.0 ML.

  • M1 = initial mass
  • V1= initial volume
  • M2 = final mass
  • V2= final volume
  • (M1V1 = M2V2)
  • (0.138)(V1) = (0.205)x(26.0)
  • V2=(0.205)x(26.0)\ 0.138
  • V2 = 47.10 M/L
  • The final value of Volume needed for neutralization of nitric acid solution is  V2 = 47.10 M/L

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How much of a sample remains after three half-lives have occurred? 1/16 of the original sample 1/9 of the original sample 1/8 of
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For this question, assume that you have 1 compound. This compound is divided in half once, so you are left with 0.5. That 0.5 that remains is divided in half again, this is the second half-life, and you are left with 0.25. The final half life involves dividing 0.25 in half, which means you are left with 0.125. For the answer to make sense, you need to know your conversions between decimals and fractions. To make it simple, if you have 0.125 and you times it by 8, you are left with your initial value of 1. Therefore, after three half-lives, you are left with 1/8th of the compound.
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