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Anton [14]
1 year ago
5

Calculate the grams of so2 gas present at stp in a 5. 9 l container. (atomic weights: s=32, o=16).

Chemistry
1 answer:
Solnce55 [7]1 year ago
8 0

The 5.9 L container at STP contains 16.83 g of SO2.

To begin, we must determine how many moles of SO2 are contained in the 5.9 L container.

At standard temperature and pressure (STP), one mole of SO2 equates to 22.4 liters.

5.9 L = 5.9 / 22.45.9 L = 0.26 moles of SO2 as a result.

The result is that 0.263 moles of SO2 are present in the container.

Following that, we shall determine the mass of 0.263 moles of SO2.

The following are ways to do this:

The mass of SO2 is 32 + (16 2) = 32 + 32= 64 g/mol,

where SO2 Mole = 0.263 Molar.

Molar + Molar Mass Equals Mass

SO2 mass is 16.83 g, or 0.263 of a kilogram.

Therefore, 16.83 g of SO2 are present in the 5.9 L container at STP.

to know more about mass, visit to:-

brainly.com/question/15959704

#SPJ4

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Below are 5 sets of potential solutes for you to compare. Both members of each pair are very soluble in water. If you had equal
Gelneren [198K]

Answer:

Option D. AlCl₃, MgC₂

Explanation:

We need to dissociate all the salts, to determine the i. (Van't Hoff factor).

The salt who has the highest value, will be the better conductor of electricity

CsCl  → Cs⁺  +  Cl⁻   i = 2

CaCl → Ca²⁺ +  Cl⁻   i = 2

CaS → Ca²⁺ +  S⁻²    i = 2

Li₂S → 2Li⁺  +  S⁻²    i = 3

KBr →  K⁺  +  Br⁻       i = 2

AlCl₃ →  Al³⁺ + 3Cl⁻   i = 4

MgC₂  →  Mg²⁺  +  2C⁻   i = 3

KI  →  K⁺  +  I⁻     i = 2

K₂S  →  2K⁺  + S⁻²   i = 3

The biggest i, is in pair D.

6 0
4 years ago
What product is released into Earth's atmosphere through the combustion of<br> fossil fuels?
mezya [45]

Answer:

Carbon Monoxide

Explanation:

Fossil fuels are hydrocarbons which only contain hydrogen and carbon.

When it is burnt in air, it reacts according to this general equation:

2(CH) + 3O2 >> H2O + CO + CO2

  • Carbondioxide
  • Carbon Monoxide
  • Water
7 0
2 years ago
Why calcium oxide and magnesium oxide used as soil treatment ​
BartSMP [9]

Answer:

Chemically speaking, lime refers only to calcium oxide

(CaO); however, in common usage the term includes the calcination products of calcitic and dolomitic limestones. Calcitic (high-calcium) limes are produced by calcination of

calcareous materials (e.g., calcitic limestone, calcite,

oyster shells, and chalk) containing from 95 to 99 percent

calcium carbonate (CaCO^). Dolomitic limes are produced from

dolomitic limestone or dolomite which contains from 30 to ^+0

percent magnesium carbonate (MgCO^), the rest being calcium

carbonate.

At atmospheric pressure, calcite in limestone decomposes

at approximately 900°C to form CaO and COg. The decomposition of dolomite, CaMg is a two-stage process. At

temperatures between 650°C to 750°C dolomite decomposes to

form MgO, CO^ and CaCO^. It is necessary to raise the temperature to 900°C to decompose the CaCO^ (15, 35)» This

phenomenon is extremely important, as is shown later.

Various investigators have studied the effects of stone

size, temperature, and time of calcination of commercial

Explanation:

4 0
3 years ago
PLSSS HELP FAST
Aliun [14]

Note the formula

\boxed{\sf Mass\:no=No\:of\:protons+No\:of\:neutrons}

For X:-

  • No of protons:-

\\ \sf\longmapsto 19-10=9protons

  • It is Fluorine.

For Y:-

  • No of protons:-

\\ \sf\longmapsto 16-8=8protons

  • It is Oxygen.

Option D is correct

7 0
2 years ago
A sample of neon initially has a volume of 2.80 L at 23 degrees Celsius. What is final temperature, in degrees Celsius, is neede
finlep [7]

The relation between the volume and the temperature of the gas is given by Charles's law. The final temperature of the gas at 0.75 liters is -193.8°C.

<h3>What is Charles's law?</h3>

Charles's law was derived from the ideal gas equation and is used to state the relationship between the temperature and the volume of the gas. With a decrease in volume the temperature decreases.

If the pressure is kept constant then with an increase in temperature the volume of the gas expands. The law is given as,

V₁ ÷ T₁ = V₂ ÷ T₂

Given,

Initial volume (V₁) = 2.80 L

Initial temperature (T₁) = 23 °C = 296.15 K

Final volume (V₂) = 0.75 L

Final temperature = T₂

Substituting the values above as:

T₂ = (V₂ × T₁) ÷ V₁

= 0.75 × 296.15 ÷ 2.80

= 79.325 K

Kelvin is converted as, 79.325K − 273.15 = -193.8°C

Therefore, the final temperature is -193.8°C.

Learn more about Charle's law, here:

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7 0
2 years ago
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