All categories

1 year ago

Calculate the grams of so2 gas present at stp in a 5. 9 l container. (atomic weights: s=32, o=16).

Chemistry

1 answer:

Solnce55 [7]1 year ago

8 0

The 5.9 L container at STP contains 16.83 g of SO2.

To begin, we must determine how many moles of SO2 are contained in the 5.9 L container.

At standard temperature and pressure (STP), one mole of SO2 equates to 22.4 liters.

5.9 L = 5.9 / 22.45.9 L = 0.26 moles of SO2 as a result.

The result is that 0.263 moles of SO2 are present in the container.

Following that, we shall determine the mass of 0.263 moles of SO2.

The following are ways to do this:

The mass of SO2 is 32 + (16 2) = 32 + 32= 64 g/mol,

where SO2 Mole = 0.263 Molar.

Molar + Molar Mass Equals Mass

SO2 mass is 16.83 g, or 0.263 of a kilogram.

Therefore, 16.83 g of SO2 are present in the 5.9 L container at STP.

to know more about mass, visit to:-

brainly.com/question/15959704

#SPJ4

You might be interested in

An atom or ion has 16 protons, 15 neutrons, and 17 electrons. Is it positive, negative, or

azamat

Its negative I think, if I remember correctly it is phosphorus-32....

7 0

2 years ago

Giving brainliest if correct!! please help someone out?

Stels [109]

Answer:

protons: 36

neutrons:48

electrons:36

Explanation:

the number of protons in an element is = to the atomic # (36)

the number of neutrons is the atomic mass - atomic # (84-36=48)

In a neutral charged element the # of protons = # of electrons

5 0

3 years ago

Determine the change in boiling point for 397.7 g of carbon disulfide (Kb = 2.34°C kg/mol) if 35.0 g of a nonvolatile, nonionizi

uysha [10]

Answer: The change in boiling point for 397.7 g of carbon disulfide (Kb = 2.34°C kg/mol) if 35.0 g of a nonvolatile, nonionizing compound is dissolved in it is $2.9^0C$

Explanation:

Elevation in boiling point:

$T_b-T^o_b=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_b$ = boiling point of solution = ?

$T^o_b$ = boiling point of pure carbon disulfide= $46.2^oC$

$k_b$ = boiling point constant = $2.34^0Ckg/mol$

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

$w_2$ = mass of solute = 35.0 g

$w_1$ = mass of solvent (carbon disulphide) = 397.7 g

$M_2$ = molar mass of solute = 70.0 g/mol

Now put all the given values in the above formula, we get:

$(T_b-46.2)^oC=1\times (2.34^oC/m)\times \frac{(35.0g)\times 1000}{70.0\times (397.7g)}$

$T_b=49.1^0C$

Therefore, the change in boiling point is $(49.1-46.2)^oC=2.9^0C$

5 0

3 years ago

2. As NH4OH is added to an HCl solution, the pH of the solution

chubhunter [2.5K]

Answer:

Explanation:

Nh4OH + HCL ---> NH4Cl + H3O

so ph decreases as H3O increases

and OH also decreases

5 0

3 years ago

Read 2 more answers

The essential oil found in cloves, eugenol, can be isolated by steam distillation because it is insoluble in water and has a mea

Damm [24]

We know that:
Molar Mass H2O: 18 g/mol
Molar Mass of Eugenol: 164 g/mol 
Boiling point of H2O: 100 degrees C 
Boiling point of Eugenol: 254 degrees C 
Density of water: 1.0 g/mL 
Density of Eugenol: 1.05 g/mL 

Using formula:
V= [mole fraction x molar mass] / density 

mH20: 0.9947 * 18
= 17.9046 / 1 g/mL
= 17.9046 
morg: 0.0053 * 164
= 0.8692/ 1.05 g/mL
= 0.8278 

V% = Vorg/(Vorg + VH2O) * 100 
(0.8278/18.7324) * 100 = 4.419% 

Yotal volume = 30 mL; therefore,
0.0442 = (volume eugenol/30) 

(m eug/mH2O) = (peug*164/pH2O*18) 
(m eug/30) = (4*164/760*18) 
m eug = about 1.44g and 

volume = mass/density
= 1.44/1.05
= about 1.37 mL

6 0

2 years ago