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Lady bird [3.3K]
3 years ago
6

Find the number of kilograms in 15.40 moles of C5H10O5

Chemistry
1 answer:
OLga [1]3 years ago
5 0
C5H10O5 would weight a total of 2.312 kilograms.
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What is the total number of grams of h2o produced when 22 grams of propane undergoes complete combustion?
SSSSS [86.1K]
The combustion reaction of propane would be expressed as:

C3H8 + 5O2 = 3CO2 + 4H2O

To determine the mass of water that is produced from the given amount of propane, we use the mass of propane and the relation of the substances from the balanced reaction. We do as follows:

moles propane = 22 g C3H8 ( 1 mol / 44.1 g ) = 0.50 mol C3H8
moles H2O = 0.50 mol C3H8 ( 4 mol H2O / 1 mol C3H8) = 2 mol H2O
mass H2O = 2 mol H2O ( 18.02 g / 1 mol ) = 36.04 g H2O

Therefore, the mass of water that is produced from 22 grams of propane would be 36.04 g.
5 0
3 years ago
Can reactions be more than one of the five types
ehidna [41]
Yes you can it will not just have 5 :)

3 0
3 years ago
1.26 * 10^4 + 2.50 * 10^4 in sceintific notation
eduard
Hello! I can help you with this. First, convert them into it’s written out standard form. 10^4 is 10,000. 10,00 * 1.26 is 12,600. 10,000 * 2.5 is 25,000. 12,600 + 25,000 = 37,600 or 3.76 * 10^4 in scientific notation. The answer in scientific notation is 3.76 * 10^4.
8 0
3 years ago
How is<br> solid different from gas ?
Orlov [11]

Answer:

gas are well separated with no regular arrangement. liquid are close together with no regular arrangement. solid are tightly packed, usually in a regular pattern.

Explanation:

5 0
3 years ago
Read 2 more answers
Is atmosphere nitrogen denser than pure nitrogen​
marusya05 [52]

Answer:

Atmospheric nitrogen is not heavier than chemical nitrogen, largely because “chemical nitrogen” is ultimately derived from atmospheric nitrogen. On the other hand, you could be asking why the atomic mass of nitrogen is not the same as the mass of nitrogen gas; that's because gaseous nitrogen is diatomic, .

Explanation:

This is from Google.

Hope this helps :))

7 0
3 years ago
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