3 years ago

Find the number of kilograms in 15.40 moles of C5H10O5

Chemistry

1 answer:

OLga [1]3 years ago

5 0

C5H10O5 would weight a total of 2.312 kilograms.

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Look at the following chemical compounds. State how many molecules of each reactant are present. (I’m sorry I’ve been working on

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$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

<h3>Compound ~ $\mathrm{NaOH}$ </h3>

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2 years ago

The number of protons in an atom is known as its atomic

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Atomic number should be the answer

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3 years ago

If the mixing ratio of a parcel of air is 6 grams per kilogram and the relative humidity is 25 percent, the saturation mixing ra

Y_Kistochka [10]

Answer: -

24 grams per kilogram.

Explanation: -

We know that

The mixing ratio = actual (measured) mass of water vapor (in parcel) in grams / mass of dry (non water vapor) air (in parcel) in kilogram

The saturation mixing ratio = mass of water vapor required for saturation (in parcel) in grams/ mass of dry (non water vapor) air (in parcel) in kilograms

Relative humidity = actual (measured) water vapor content/ maximum possible water vapor amount (saturation)

Thus saturation mixing ratio = Mixing ratio / relative humidity

= 6 / (25/100)

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