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-BARSIC- [3]
1 year ago
5

The earth's tectonic plates are directly propelled by the convection in the __________.

Physics
1 answer:
frozen [14]1 year ago
3 0

The missing word here is <u>Asthenosphere.</u><u> </u>

The convection in the asthenosphere directly propels the tectonic plates of the earth.


Did you know that the asthenosphere is thought to remain malleable because of heat from deep within the Earth? It is thought to be lubricating the earth's tectonic plates' undersides and enabling movement.


The older, denser portions of the lithosphere that are dragged downward in subduction zones are stored in the asthenosphere, according to the theory of plate tectonics.

The lithosphere above is stressed by convection currents, and the cracking that frequently results manifests as earthquakes.

Magma is forced upward through volcanic vents and spreading centers by convection currents produced within the asthenosphere, which also results in the formation of new crust.

Learn why properties of the asthenosphere are important: brainly.com/question/11484043

#SPJ4

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What is the gravitational force between two identical 5000 kg asteroids whose centers of mass are separated by 100 m?
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Answer: 1.67 x 10^-7N

Explanation:

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3 years ago
A physical pendulum in the form of a planar object moves in simple harmonic motion with a frequency of 0.290 Hz. The pendulum ha
BARSIC [14]

Answer:

1.4584 kgm^2

Explanation:

Time period of a physical pendulum is given by T=2Π\sqrt{\frac{I}{mgd}}

Here f=0.290 so T=\frac{1}{F}=\frac{1}{0.29}=3.44827

Mass =2.40 kg

d=0.300 m

g =9.8 msec^2

So 3.448=2\times \pi \sqrt{\frac{I}{2.4\times 9.81\times 0.300}}=1.4584  kg-m^2

So the moment of inertia of the pendulum about the pivot point will be 1.4584 kg-m^2

7 0
3 years ago
Two cars start a race with initial velocity 7ms-1 and 4ms-1 respectively.Their acceleration are 0.4ms-2 and 0.5ms-2 respectively
Ronch [10]

The distance of the track is 600 m

Explanation:

The two cars move by uniformly accelerated motion, so we the distance they cover after a time t is described by the following suvat equation

d=ut+\frac{1}{2}at^2

where

u is the initial velocity

a is the acceleration

For car 1, we have

d_1 = u_1 t + \frac{1}{2}a_1 t^2

where

u_1 = 7 m/s is the initial velocity of car 1

a_1 = 0.4 m/s^2 is the acceleration of car 1

So the equation can be rewritten as

d_1 = 7t + 0.2t^2

For car 2, we have

d_2 = u_2 t + \frac{1}{2}a_2 t^2

where

u_2 = 4 m/s is the initial velocity of car 2

a_2 = 0.5 m/s^2 is the acceleration of car 2

So the equation can be rewritten as

d_2= 5t + 0.25t^2

The two cars finish the race at the same time: this means that they cover the same distance in the same time t, so we can write

d_1 = d_2\\7t + 0.2t^2=5t + 0.25t^2

And solving for t, we find

2t - 0.05t^2= 0\\t(2-0.05t)=0

Which gives two solutions:

t = 0 (initial instant)

t = 40 s

Therefore, the distance of the track is

d_1 = 7t +0.2t^2 = 7\cdot 40+0.2\cdot 40^2=600 m

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

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Answer:

Option B (1.51 m)

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