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Lapatulllka [165]
3 years ago
13

ভিতে ২০২০ শিকাৰৰে পুনর্বিন্যাসকৃত পাঠ্যসূচি জিভে জ্যাসাইনমেন্ট নিতে চাজ ওয়েন সিত

Physics
1 answer:
AURORKA [14]3 years ago
5 0

harjot singh answer hai bro

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A charged particle moves through a velocity selector at a constant speed in a straight line. The electric field of the velocity
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Answer:

The charge-to-mass ratio of the particle is 5.7 × 10⁵ C/kg

Explanation:

From the formulae

F = qvB and F = mv²/r

Where F is Force

q is charge

v is speed

B is magnetic field strength

m is mass

and r is radius

Then,

qvB = mv²/r

qB = mv/r

We can write that

q/m = v/rB ---- (1)

Also

From Electric force formula

F = Eq

Where E is the electric field

and magnetic force formula

F = Bqv

Since, electric force = magnetic force

Then, Eq = Bqv

E = Bv

∴ v = E/B

Substitute v = E/B into equation (1)

q/m = (E/B)/rB

∴ q/m = E/rB²

(NOTE: q/m is the charge to mass ratio)

From the question,

E =  3.10 ×10³ N/C

r = 4.20 cm = 0.0420 m

B = 0.360 T

Hence,

q/m = 3.10 ×10³ / 0.0420 × (0.360)²

q/m = 569517.9306 C/kg

q/m = 5.7 × 10⁵ C/kg

Hence, the charge-to-mass ratio of the particle is 5.7 × 10⁵ C/kg.

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What is polarization. How can we remove it?
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Which of the following is not a common property of basesp
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Explanation:

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Explain how the property of density is applied and used in the real world
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Answer:

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HOPE IT HELPS

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