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Gre4nikov [31]
2 years ago
12

For an object on a flat surface, the force of gravity is 10 newtons downward and the normal force is 10 newtons upward. The appl

ied force is 15 newtons toward the right and the frictional force is 12 newtons toward the left. What is the magnitude and direction of the net force?
3 newtons toward the left
3 newtons upward
3 newtons downward
3 newtons toward the right
Physics
1 answer:
bezimeni [28]2 years ago
3 0
3 Newtons toward the right because Newton’s second law:
F = ma
15N - 12N = ma
3N = ma
(With the right being the positive direction and the left the negative direction)
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To understand thermal linear expansion in solid materials. Most materials expand when their temperatures increase. Such thermal
Marat540 [252]

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

5 0
2 years ago
A 60KG WOMAN IS ON A LADDER 2 M ABOVE THE GROUND. WHAT IS HER POTENTIAL ENERGY
dexar [7]

Answer:

Explanation:

PE = mgh = 60(9.8)(2.0) = 1176 J

7 0
2 years ago
A motorcycle of mass 100 kilograms slowly rolls off the edge of a cliff and falls for three seconds before reaching the bottom o
Jet001 [13]

Answer:

C) 3,000 kg m/s

Explanation:

We can consider the horizontal velocity of the motorcycle to be zero, since it rolls off the edge of the cliff very slowly. So, we only need to find the vertical velocity at the time of the impact with the ground.

The vertical velocity of the motorcycle at time t is given by (free-fall motion):

v(t)=v_0 -gt

where

v_0=0 is the initial vertical velocity (zero, since the motorcycle is not moving)

g = 9.8 m/s^2 is the acceleration due to gravity

t is the time

Since the motorcycle hits the ground after t = 3 seconds, we have

v(3 s)=0-(9.8 m/s^2)(3 s)=-29.4 m/s

And since we know its mass, m=100 kg, we can find its momentum:

p=mv=(100 kg)(-29.4 m/s)=-2940 kg m/s \cdot -3000 kg m/s

and the negative sign simply means downward direction.

8 0
3 years ago
The air temperature in a 28 in.3 container with a free sliding piston is initially measured at 45 °
sergiy2304 [10]

To solve this we assume that the gas inside is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

T1 / V1 = T2 / V2

V2 = T2 x V1 / T1

V2 = 659.7 x 28 / 504.7

<span>V2 = 36.60 in^3</span>

8 0
3 years ago
A spring is mounted horizontally, with its left end fixed. A spring balance attached to the free end and pulled toward the right
malfutka [58]

Answer:

200 N/m

20 rad/s

0.31415 seconds

3.18309 Hz

Explanation:

m = Mass of glider = 0.5 kg

x = Displacement of spring

F = Force on spring = 6 N

From Hooke's law we have relation

F=kx\\\Rightarrow k=\frac{F}{x}\\\Rightarrow k=\frac{6}{0.03}\\\Rightarrow k=200\ N/m

The spring constant is 200 N/m

Angular frequency is given by

\omega=\sqrt{\frac{k}{m}}\\\Rightarrow \omega=\sqrt{\frac{200}{0.5}}\\\Rightarrow \omega=20\ rad/s

The angular frequency is 20 rad/s

Frequency is given by

f=\frac{\omega}{2\pi}\\\Rightarrow f=\frac{20}{2\pi}\\\Rightarrow f=3.18309\ Hz

The frequency is 3.18309 Hz

Time period is given by

T=\frac{1}{f}\\\Rightarrow T=\frac{1}{3.18309}\\\Rightarrow T=0.31415\ s

The time period is 0.31415 seconds

6 0
3 years ago
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