Answer:Wrap more turns of wire around the nail.
Explanation:The power of an electromagnet is directly proportional to the amount of electricity passing through that electromagnet.
Now,if they increase the number of rounds of the copper coil,the electricity conducting surface amount will also increase.
And that's why the electricity passing through that electromagnet will increase along with the electromagnetic power of that electromagnet.
• Increasing the battery voltage :
If they increase the battery voltage,the electricity which is passing through that electromagnet will also increase in amount .
And as discussed previously,the increasing amount of electricity will also increase the electromagnetic abilities of the electromagnet.
Things are rubbed against each other
Answer: <em>An object at rest remains at rest, or if in motion, remains in motion at a constant velocity unless acted on by a net external force.</em>
Explanation: meaning, an object will continue in its same direction until stopped or acted upon by another force.
Answer:
β₂ = 88.8 dβ
Explanation:
The intensity of the sound is
β = 10 log (I / I₀)
The sensitivity threshold (I₀) for humans is 1 10⁻¹² W / m²
I = I₀
I = 10⁻¹² 10^{70/10}
I = 1 10⁻⁵ W / m²
The total intensity for the 76 trombones is
I_total = n I
I_total = 76 1 10⁻⁵
I_total = 76 10⁻⁵ W / m²
Let's find the sound level
β₂ = 10 log (76 10⁻⁵ / 10⁻¹²)
β₂ = 88.8 dβ
(a) The angular position of the door is described by
![\theta(t)=5+10t+2t^2 [rad]](https://tex.z-dn.net/?f=%5Ctheta%28t%29%3D5%2B10t%2B2t%5E2%20%5Brad%5D)
The angular velocity is given by the derivative of the angular position:
![\omega(t)=10+4t [rad/s]](https://tex.z-dn.net/?f=%5Comega%28t%29%3D10%2B4t%20%5Brad%2Fs%5D)
While the angular acceleration is given by the derivative of the angular velocity:
![\alpha(t)=4 [rad/s^2]](https://tex.z-dn.net/?f=%5Calpha%28t%29%3D4%20%5Brad%2Fs%5E2%5D)
We want to find the values of these quantities at time t=3.00 s, so we must substitute t=3.00 s into the expressions for

:



(b) The door starts from rest, so its initial angular velocity is

, and it reaches a final angular velocity of

with an angular acceleration of

. We can find the angular distance covered by the door by using the following relationship:

from which we find