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Hatshy [7]
3 years ago
6

Sara and Greg built an electromagnet in science class. They wrapped 50 turns of copper wire around an iron nail and hooked the e

nds of the wire to a 1.5 volt battery. They picked up 15 paper clips with their electromagnet, but they want to make it stronger. What should they do?
A) Decrease the battery size.
B) Use a nail with a galvanized coating.
C) Wrap more turns of wire around the nail.
D) Replace the iron nail with a piece of steel.
Physics
2 answers:
frez [133]3 years ago
7 0

Answer:

C)

Explanation:

Iteru [2.4K]3 years ago
4 0

Answer:Wrap more turns of wire around the nail.

Explanation:The power of an electromagnet is directly proportional to the amount of electricity passing through that electromagnet.

Now,if they increase the number of rounds of the copper coil,the electricity conducting surface amount will also increase.

And that's why the electricity passing through that electromagnet will increase along with the electromagnetic power of that electromagnet.

• Increasing the battery voltage :

If they increase the battery voltage,the electricity which is passing through that electromagnet will also increase in amount .

And as discussed previously,the increasing amount of electricity will also increase the electromagnetic abilities of the electromagnet.

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3 years ago
An empty 2,500 kg train car is headed northbound at a velocity of 5 m/s. Ahead of the first car, an empty 1,500 kg car is headed
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Let the mass of 2500 kg car be m_1 and it's velocity be v_1 and the mass of 1500 kg car be m_2 and it's velocity be v_2 .

After the bumping the mass be M and it's velocity be V.

     By law of conservation of momentum we have

                   m_1v_1+m_2v_2 = MV

                    2500 * 5 + 1500 * 1=4000 * V

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A car is traveling at 15 m/sm/s . Part A How fast would the car need to go to double its kinetic energy
GREYUIT [131]

Answer:

21.21 m/s

Explanation:

Let KE₁ represent the initial kinetic energy.

Let v₁ represent the initial velocity.

Let KE₂ represent the final kinetic energy.

Let v₂ represent the final velocity.

Next, the data obtained from the question:

Initial velocity (v₁) = 15 m/s

Initial kinetic Energy (KE₁) = E

Final final energy (KE₂) = double the initial kinetic energy = 2E

Final velocity (v₂) =?

Thus, the velocity (v₂) with which the car we travel in order to double it's kinetic energy can be obtained as follow:

KE = ½mv²

NOTE: Mass (m) = constant (since we are considering the same car)

KE₁/v₁² = KE₂/v₂²

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Cross multiply

E × v₂² = 225 × 2E

E × v₂² = 450E

Divide both side by E

v₂² = 450E /E

v₂² = 450

Take the square root of both side.

v₂ = √450

v₂ = 21.21 m/s

Therefore, the car will travel at 21.21 m/s in order to double it's kinetic energy.

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