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3 years ago

The approximate mass of a nickel in kilograms is

Physics

1 answer:

mart [117]3 years ago

5 0

The nickel has a mass of approximately 0.005kg

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The Mars Curiosity rover was required to land on the surface of Mars with a velocity of 1 m/s. Given the mass of the landing veh

Aliun [14]

Answer:

The value is $A = 39315 \ m^2$

Explanation:

From the question we are told that

The velocity which the rover is suppose to land with is $v = 1 \ m/s$

The mass of the rover and the parachute is $m = 2270 \ kg$

The drag coefficient is $C__{D}} = 0.5$

The atmospheric density of Earth is $\rho = 1.2 \ kg/m^3$

The acceleration due to gravity in Mars is $g_m = 3.689 \ m/s^2$

Generally the Mars atmosphere density is mathematically represented as

$\rho_m = 0.71 * \rho$

=> $\rho_m = 0.71 * 1.2$

=> $\rho_m = 0.852 \ kg/m^3$

Generally the drag force on the rover and the parachute is mathematically represented as

$F__{D}} = m * g_{m}$

=> $F__{D}} = 2270 * 3.689$

=> $F__{D}} = 8374 \ N$

Gnerally this drag force is mathematically represented as

$F__{D}} = C__{D}} * A * \frac{\rho_m * v^2 }{2}$

Here A is the frontal area

$A = \frac{2 * F__D }{ C__D} * \rho_m * v^2 }$

=> $A = \frac{2 * 8374 }{ 0.5 * 0.852 * 1 ^2 }$

=> $A = 39315 \ m^2$

8 0

3 years ago

Who was the carthaginian general who used elephants to cross the alps in the second punic war

goldfiish [28.3K]

the answer is Hannibal

3 0

3 years ago

Read 2 more answers

What is the Orbital Notation for Radon

Marina CMI [18]

Answer:

[Rn]7s2

Explanation:

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3 years ago

The heat energy gained by the water in one minute is ?

kari74 [83]

fast-moving particles colliding with slow-moving particles

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3 years ago

A granite monument has a volume of 25,365.4 cm. The density of granite is 2.7 g/cms. Use this information to calculate the mass

olchik [2.2K]

Answer:

m = 68,486,6 g is the answer.

Explanation:

To calculate mass you use formula:

m= V*r

To avoid remembering this formula you can see the type of unit on each given variable. We can see that we have g/cm^3 and cm^3. If we multiply them, we negate cm^3 and cm^3 and we are left with g which is unit for mass.

Hope I helped! ☺

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3 years ago