Answer:
v = 7.32 m/s
Explanation:
The potential energy will convert to kinetic energy
½Iω² + ½mv² = mgh
Iω² + mv² = 2mgh
(½mR²)(v/R)² + mv² = 2mgh
½mv² + mv² = 2mgh
½v² + v² = 2gh
3v²/2 = 2gh
v² = 4gh/3
v² = 4(9.81)(4.10)/3
v² = 53.628
v = 7.323114...
v = 7.32 m/s
Answer:
Explanation:
Given that,
Electric field E=135V/m
Energy stored in 1m³of air=?
The energy stored in an electric field is given as
u = ½ εo E²
Where
U is the energy stored
εo is permissivity and it value is 8.85×10^-12C²/N..m²
And E is the electric field
Then,
U=½×8.85×10^-12×135²
U=8.06×10^-8J/m³
Then, the energy stored in 1m³ of air is 8.06×10^-8 J/m³
Best answer must be false. Because the IMA it doesn't have always stay smaller than the AMA. Hope it helped you!
Joule (J) is the metric unit for energy
