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BartSMP [9]
3 years ago
11

How many moles of aluminum oxide are formed from 10.3 moles of Aluminum?

Chemistry
1 answer:
MissTica3 years ago
5 0

Answer:

Equation of reaction

2Al + 3O_ Al2O3

2 moles of Al _ 1 mole of Al2O3

10.3 moles of Al _ x mole of Al2O3

x =(10.3 × 1)/ 2 =5.15 mole

Therefore, 10.3 moles of Aluminum gives 5.15 moles of Aluminum oxide.

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What is the maximum mass, in kilograms, of (NH4)2U2O7 that can be formed from the reaction of 100 kg of water and 100 kg of ammo
V125BC [204]

Mass of (NH₄)₂U₂O₇ : 410.05 kg

<h3>Further explanation</h3>

Reaction

2UO₂SO₄ + 6NH₃ + 3H₂O → (NH₄)₂U₂O₇ + 2(NH₄)₂SO₄

MW UO₂SO₄ :  366.091

MW (NH₄)₂U₂O₇ : 624.131

MW H₂O :  18.0153

MW NH₃ : 17.0306

mol of 100 kg water :

\tt \dfrac{100}{18.0153}=5.55

mol of 100 kg ammonia :

\tt \dfrac{100}{17.036}=5.87

mol of UO₂SO₄ :

\tt \dfrac{481}{366.091}=1.314

Limiting reactants : smallest mol ratio(mol : coefficient)

\tt \dfrac{5.55}{3}\div \dfrac{5.87}{6}\div \dfrac{1.314}{2}=1.85\div 0.98\div 0.657

UO₂SO₄ ⇒ Limiting reactants

mol (NH₄)₂U₂O₇ : mol UO₂SO₄

\tt \dfrac{1}{2}\times 1.314=0.657

mass (NH₄)₂U₂O₇

\tt 0.657\times 624.131=410.05

5 0
3 years ago
Draw the structures of organic compounds a and b omit all by products thf
Brums [2.3K]
The reaction is shown below,

Step 1: Hydration of Alkene:
                                            In first step Ethene is hydrated to Ethanol through Hydroboration Reaction.

Step 2: Oxidation of Primary Alcohol:
                                                          In this step partial oxidation of ethanol is carried out using mild Oxidizing agent <span>Pyridinium chlorochromate (PCC) and Acetaldehyde is produced.

Step 3: Reduction of Acetaldehyde followed by Oxidation:
                                                                                           In this step, first acetaldehyde is reduced to secondary alcohol using grignard reagent. After that the sec. alcohol is oxidized to ketone by using oxidizing agent CrO</span>₃.

6 0
3 years ago
For the reaction N2(g) + 3H2(g) ↔ 2NH3(g), the equilibrium constant, K, = 9.83 x 10-2 at a certain temperature and pressure.
pshichka [43]

The reaction is not at equilibrium and it is in the forward direction.

a.

Given,

[N₂] = 0.910 mol / L

[H₂] = 0.3 mol / L

[NH₃] = 0.0081 mol / L

K = 9.83 x 10⁻²

The balanced chemical equation for the given reaction is,

N₂(g) + 3H₂(g) ⇄ 2NH₃(g)

The formula of equilibrium constant is given by,

K = [NH₃]² / [N₂] [H₂]²

9.83 x 10⁻² = [(0.0081)² ]/ [0.910 × (0.3)²]

⇒9.83 x 10⁻² = (0.00006561) / (0.0819)

⇒9.83 x 10⁻² = 0.0008010989

⇒0.00983 = 0.0008010989

LHS ≠ RHS

Hence, the reaction is not at equilibrium.

b.

The reaction is in forward direction.

Learn more about direction of the reaction from the link given below.

brainly.com/question/10278602

#SPJ1

4 0
2 years ago
A gas has a volume of 450.0 ml at standard pressure. If the temperature is held constant, what volume would the gas occupy if th
zimovet [89]
A. 1800L !:$:!:):&/&/?)3&2!3?372&2!3)3$3!3!3?3:$heguejeneve
6 0
3 years ago
Explain what needs to happen for the box to start moving
VMariaS [17]

Answer:

It needs an force in the opposite direction.

Explanation:

Example:

The box is on a flat surface. You use your hands to push it. You have to push it in the opposite direction.

4 0
3 years ago
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