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malfutka [58]
2 years ago
7

What is the gauge pressure at point A when spigot C is closed?

Physics
1 answer:
Nesterboy [21]2 years ago
3 0

Given,

\begin{gathered} l_1=0.2m \\ l_2=0.07m \\ h=0.47m \\ \rho=\frac{1g}{cm^3} \end{gathered}

Atm

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A. while<br>to rest<br>coming<br>down from a slide<br>you stop and come​
Pani-rosa [81]
Ok ok ok ok ok ok I ok ok I I’m only on kn knkkkm I’m on
3 0
3 years ago
Calcular el módulo del vector resultante de dos vectores fuerza de 9 [N] y 12 [N] concurrentes en un punto o, cuyas direcciones
sdas [7]

Answer:

a) 20.29N

b) 19.43N

c) 15N

Explanation:

To find the magnitude of the resultant vectors you first calculate the components of the vector for the angle in between them, next, you sum the x and y component, and finally, you calculate the magnitude.

In all these calculations you can asume that one of the vectors coincides with the x-axis.

a)

F_R=(9cos(30\°)+12)\hat{i}+(9sin(30\°))\hat{j}\\\\F_R=(19.79N)\hat{i}+(4.5N)\hat{j}\\\\|F_R|=\sqrt{(19.79N)^2+(4.5N)^2}=20.29N

b)

F_R=(9cos(45\°)+12)\hat{i}+(9sin(45\°))\hat{j}\\\\F_R=(18.36N)\hat{i}+(6.36N)\hat{j}\\\\|F_R|=\sqrt{(18.36N)^2+(6.36N)^2}=19.43N

c)

F_R=(9cos(90\°)+12)\hat{i}+(9sin(90\°))\hat{j}\\\\F_R=(12N)\hat{i}+(9N)\hat{j}\\\\|F_R|=\sqrt{(12N)^2+(9N)^2}=15N

7 0
3 years ago
the inductive reactance of a 20.0-mh inductor at a certain frequency is 120 ω. what is the frequency in hz?
QveST [7]

The inductive reactance of a 20.0-mh inductor at a certain frequency is 120 ω. 955hz is the frequency in hz

In physics, frequency is the number of waves that pass a fixed point in a unit of time as well as the number of cycles or vibrations that a body in periodic motion experiences in a unit of time.

How frequently something occurs is what is meant by the word frequency. A person blinking their eyelids 47 times in a minute is an example of frequency. the quality or state of happening frequently.

Frequency is a numerical value that expresses how frequently a specific item appears in the supplied data set. Grouped frequency distribution and Ungrouped In physics, frequency is a numerical value that expresses how frequently a specific item appears in the supplied data set. Distribution are the two different types of frequency tables.

To learn more about frequency please visit brainly.com/question/5102661
#SPJ4

6 0
2 years ago
Read 2 more answers
During a rodeo, a clown runs 7.7 m north, turns 49.9 degrees east of north, and runs 6.4 m. Then after waiting for the bull to c
IRINA_888 [86]

During a rodeo, a clown runs 7.7 m north, turns 49.9 degrees east of north, and runs 6.4 m. Then after waiting for the bull to come near, the clown turns due east and runs 19.8 m to exit the arena. The magnitude of the clown’s displacement is 27 m.

<u>Explanation: </u>

As the clown is running in the north direction for about 7.7 m and then he turns 49.9 degrees east of north. In the east of north, he covers a distance of 6.4 m and then turns east to exit the arena after covering a distance of 19.8 m. Let’s have a simple diagram to easily understand the problem.

In first step, the clown runs 7.7 m in north direction, so the image will be  as in fig 1. Then he takes a direction of north east and covers a distance of 6.4 m, so the image will be modified as in fig 2. Then after the bull comes, he turns east and runs 19.8 m to exit the arena, so the image will be as in figure 3.

So, the extension of North line and the East line at a point shown as the dotted line in the above image, forms the total displacement as the hypotenuse of a right angled triangle. The extended dotted lines is nothing but the horizontal and vertical components of the angle 49.9 degree.

By using Pythagoras theorem, the total displacement can be found as

\text { Total displacement }=\sqrt{(o p p)^{2}+(a d j)^{2}}

\text { Distance covered by the clown in east direction }=(6.4 \times \cos 49.9)+19.8=23.9 \mathrm{m}

Similarly, the adjacent side of this imaginary triangle is the distance covered by the clown in the North direction.

\text { Distance covered by the clown in north direction }=6.4 \sin 49.9+7.7=12.6 \mathrm{m}

Thus, the total displacement covered by the clown is

\text { Total displacement }=\sqrt{(23.9)^{2}+(12.6)^{2}}=\sqrt{571.21+158.76}=\sqrt{729.97}=27 \mathrm{m}

Thus, the total displacement by the clown is 27 m.

5 0
3 years ago
If the mass is 22 g and the volume is 11 ml, what is the density of the object
andriy [413]
2 g/mL there’s your answer
8 0
3 years ago
Read 2 more answers
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